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Vesna [10]
3 years ago
9

In most energy sources, such as fossil fuels, where is the energy originally derived from?

Physics
2 answers:
DaniilM [7]3 years ago
8 0

The sun is the aswer so A is correct hope this helps you!!!!

N76 [4]3 years ago
3 0
The sun is the actual source of energy for us
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We have a long wire with a circular cross section and radius a = 2.40 cm. The current density in this wire is uniform, with a to
Alika [10]

Answer:

The magnitude of the magnetic field is 7.49x10⁻⁶T

Explanation:

The magnetic field is:

B=(\frac{\mu i}{2\pi R^{2} } )r

Where

i = current = 3 A

R = radius = 2.4 cm = 0.024 m

r = distance = 0.72 cm = 7.2x10⁻³m

Replacing:

B=(\frac{4\pi x10^{-7} *3}{2\pi *0.024^{2} } )*7.2x10^{-3}= 7.49x10^{-6} T

7 0
3 years ago
Which describes an INHERITED TRAIT of a plant?
Ronch [10]

Answer: the green color of a leaf

Explanation: because the other things are physical changes of a plant that don't get passes down to offspring

7 0
3 years ago
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In a Young’s interference experiment, the two slits are separated by 0.150 mm and the incident light includes two wavelengths: l
dezoksy [38]

Answer:

2.52 × 10⁻² cm

Explanation:

The distance of bright fringe from the center of the screen is given by the formula

                y = \frac{m\lambda D}{d}

Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the

slits is d.

   

Separation between the slits, d = 0.15 mm

                                                     = 0.15 * 10^{-3} m

Distance of the screen from the slits = 1.40 m

We have a wavelength, λ1 = 540 nm

                                           = 540 * 10^{-9} m

By substituting all these values in the above equation we get

                y1 = mλD/d

                y1 = m(540 \times 10^{-9} m)(1.40 m)/(0.15 \times 10^{-3} m)

                y1 = m(5.04 * 10^{-3} m)

We have a wavelength, λ2 = 450 nm

                                           = 450 * 10^-9 m

By substituting all these values in the above equation we get

                y_2 = \frac{m\lambda D}{d}

                y_2 = m(450 * 10^{-9} m)(1.40 m)/(0.15 * 10^{-3} m)

                y_2 = m'(4.20 * 10^{-3} m)

According to the problem, these two distance are coincides with each other.

So,

                           y_1 = y_2

m(5.04 * 10^{-3} m) = m'(4.20 * 10^{-3} m)

by testing values, the above equation is satisfied only when, m = 5 and m' = 6

Then from the above we have

                           y1 = y2 = 0.0252 m

                                         = 2.52 × 10⁻² cm

8 0
3 years ago
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone brid
dalvyx [7]

Answer:

The balanced condition for Wheat stones bridge is  

Q

P

​  

=  

S

R

​  

 

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

​  

=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

Explanation:

8 0
3 years ago
If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
steposvetlana [31]

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0
3 years ago
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