Answer:
Tycho's data let Kepler refine his model for planetary motion. It led him to create what we today call Kepler's three laws of planetary motion. The first law of planetary motion states: Planets move around the sun in an elliptical orbit, where the sun is one of the foci.
Explanation:
Johannes Kepler's most influential accomplishments in astronomy were his three Laws of Planetary Motion, which were used by Isaac Newton to develop his theory of universal gravitation.
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Answer:
Explanation:
Sine the plane is horizontal , effect of gravity on horizontal motion will be nil.
Since no friction is acting on it , no horizontal force is acting on it. Since no vertical ,no horizontal force is acting on it , it will have uniform motion ,ie its velocity will remain unchanged during its motion , no matter how long the path is.
So , velocity along the path will remain unchanged.
Answer:
Explanation:
Answer:
Explanation:
Given that,
System of two particle
Ball A has mass
Ma = m
Ball A is moving to the right (positive x axis) with velocity of
Va = 2v •i
Ball B has a mass
Mb = 3m
Ball B is moving to left (negative x axis) with a velocity of
Vb = -v •i
Velocity of centre of mass Vcm?
Velocity of centre of mass can be calculated using
Vcm = 1/M ΣMi•Vi
Where M is sum of mass
M = M1 + M2 + M3 +...
Therefore,
Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb
Rearranging for better understanding
Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)
Vcm = (m•2v + 3m•-v) / (m + 3m)
Vcm = (2mv — 3mv) / 4m
Vcm = —mv / 4m
Vcm = —v / 4
Vcm = —¼V •i
Answer:
Specific heat
Explanation:
The specific heat is the amount of heat, that is energy in transfer to or from a thermodynamic system, required to raise the temperature of 1 g of substance by one degree Celsius or one Kelvin, since one degree on the Celsius scale is equal to one Kelvin.
Answer:
y = 2.76 [m]
Explanation:
We can find the distance of the fall of the apple using the following kinematic equation, we have to emphasize that this is a typical problem of free fall, so the initial speed is zero, then we give the initial data.
t = time = 0,75[s]
g = gravity = 9.81[m/s^2]
v0 = 0
![y = v_{0}*t+0.5*g*t^{2}\\ y=0.5*(9.81)*(0.75)^{2}\\y= 2.76[m]](https://tex.z-dn.net/?f=y%20%3D%20v_%7B0%7D%2At%2B0.5%2Ag%2At%5E%7B2%7D%5C%5C%20y%3D0.5%2A%289.81%29%2A%280.75%29%5E%7B2%7D%5C%5Cy%3D%202.76%5Bm%5D)