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Phoenix [80]
3 years ago
10

One of your fellow students comes up to you and asks the following question, "If an object is not moving, can it be accelerating

?" Based on your prior knowledge of this topic, what is the best response? A). Yes, becuase acceleration depends on the rate of change of velocity and not the value of velocity itself.
B). No, acceleration and velocity are equivalent, so if one equals zero, the other must also equal zero.
D). Yes, but only if the object's acceleration is very small.
D). Yes, but only if the acceleration is negative in order to keep velocity equal to zero.
Physics
1 answer:
ipn [44]3 years ago
3 0

Answer:

correct answer is option A (Yes, becuase acceleration depends on the rate of change of velocity and not the value of velocity itself.)

Explanation:

we know that from first equation of motion,

v=u+at

0r

a=\frac{v-u}{t}............(1)

here,

v-final velocity

u-initial velocity

a-acceleration

t-time

if a body is not moving it means if its initial velocity is zero (u=0) and if after time t it moves with velocity v then its acceleration will be given as

a=\frac{v}{t}...........(2)

From above equation it is clear that if an object is not moving, it can be accelerating because acceleration depends on rate of change of velocity and not the value of velocity itself.

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Which one has greater potential energy? An 8 kg rock sitting on a 2.2 m cliff or a 6 kg rock sitting on a 3.2 m cliff.
Evgesh-ka [11]

Answer: The 6 kg rock sitting on a 3.2 m cliff.

Explanation:

The potential energy of an object of mass M that is at a height H above the ground us:

U = M*H*g

where g is the gravitational acceleration:

g = 9.8m/s^2

Then:

"An 8 kg rock sitting on a 2.2 m cliff"

M = 8kg

H = 2.2m

U = 8kg*2.2m*9.8 m/s^2 = 172.48 J

"a 6 kg rock sitting on a 3.2 m cliff"

M = 6kg

H = 3.2m

U = 6kg*3.2m*9.8m/s^2 = 188.16 J

You can see that the 6kg rock on a 3.2m cliff has a larger potential energy.

6 0
3 years ago
A series of pulses, each of amplitude 0.1m , is sent down a string that is attached to a post at one end. The pulses are reflect
sp2606 [1]

The net displacement at a point on the string where the pulses cross is 0.2 m.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the ends are free.

There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.

Now, since A = 0.1 m

Then, 2A = 2(0.1) = 0.2 m

As a result, the net displacement at the string's intersection of two pulses is 0.2 m.

The correct option is (c).

Learn more about amplitude here:

brainly.com/question/3613222

#SPJ4

4 0
2 years ago
9. If the musician hit the drum on a stage, how would the sound wave behave differently if he hit it the drum if the drum were s
egoroff_w [7]
I think it would be yes because the drum is submerged in water and the water would slow the sound waves, making the sound softer. Right?
4 0
3 years ago
Two ropes are attached to either side of a 100.0 kg wagon as shown below. The rope on the right is pulled at an angle 40.0° rela
NikAS [45]

The acceleration of the wagon is found by applying Newton's Second Law of motion.

1. The responses for question 1 are;

  • x-component of the tension in the rope on the right is approximately <u>91.93 N</u>
  • y-component of the tension in the rope on the right is approximately <u>71.135 N</u>
  • x-component of the tension in the rope on the left is -80.0 N
  • y-component of the tension in the rope on the left is 0

2. The net force in the x-direction is approximately <u>11.93 N</u>

3. The net acceleration of the wagon in the horizontal direction is approximately <u>0.1193 m/s²</u>.

Reasons:

The given parameters are;

Mass of the wagon, m = 100.0 kg

Angle of inclination to the horizontal of the rope to the right, θ = 40.0°

Tension in the rope on the right = 120.0 N

Direction in which the rope on the left is pulled = To the west

Tension in the rope on the left = 80.0 N

1. The <em>x</em> and <em>y</em> component of the tension in the rope on the right are;

x-component = 120.0 N × cos(40.0°) ≈ <u>91.93 N</u>

y-component = 120.0 N × sin(40.0°) ≈ <u>77.135 N</u>

The <em>x</em> and <em>y</em> component of the tension in the rope on the left are;

x-component = 80.0 N × cos(180°) = <u>-80.0 N</u>

y-component = 80.0 N × sin(180°) = <u>0.0 N</u>

2. The net force in the horizontal direction, Fₓ, is found as follows;

Fₓ = The x-component of the rope on the left + The x-component of the rope on the right

Which gives;

Fₓ = 91.93 N - 80.0 N = <u>11.93 N</u>

3. The net acceleration of the block is given as follows;

According to Newton's Second Law of motion, we have;

Force in the horizontal direction, Fₓ = Mass of wagon, m × Acceleration of the wagon in the horizontal direction, aₓ

Fₓ = m × aₓ

Therefore;

\displaystyle a_x = \frac{F_x}{m}  \approx \frac{11.93 \, N}{100.0 \, kg} = \mathbf{0.1193 \ m/s^2}

  • The acceleration of the wagon in the horizontal direction, aₓ ≈ <u>0.1193 m/s²</u>.

Learn more here:

brainly.com/question/20357188

8 0
3 years ago
Whose geocentric model of the solar system was accepted for 1400 years
-BARSIC- [3]

Answer:

Plato, Aristotle developed it further and used for 1400 years till Copernicus.

Explanation:

8 0
3 years ago
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