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storchak [24]
4 years ago
11

Help pleaseee...A grocery store sells a bag of 7 oranges for $4.48. If Khloe spent $6.40 on oranges,

Mathematics
1 answer:
Kaylis [27]4 years ago
4 0

Answer:

10

Step-by-step explanation:

7 oranges over 4.48 dollars= x over 6.4 dollar

cross multiply and solve for x

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Rewrite the expression by combining like terms. 3y + 5x2 + 10x + 2x2 + 15x – 3y​
EleoNora [17]

Answer:

7x²+ 25x

Step-by-step explanation:

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3 years ago
At 3:00 PM a man 138 cm tall casts a shadow 148 cm long. At the same time, a tall building nearby casts a shadow 199 m long. How
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The answer is 51 Meters. I subtracted the man from the building and it's 51 meters.

3 0
3 years ago
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HELP ME PLZZ I NEED HELP WITH THIS
Natali5045456 [20]

Answer:

5 cups

The Commutative Property of Addition

Step-by-step explanation:

They have a common denominator of 12

21/12+6/12+20/12+4/12+3/12+6/12=60/12=5 cups

or you could group ingredients with the same denominators

7/4+1/4+1/2+1/2+5/3+1/3=

8/4+2/2+6/3=

2+1+2=5

The Commutative Property of Addition says the order of the numbers doesn’t change the outcome.

8 0
4 years ago
X2-8x+10=0 solve for x
Oksi-84 [34.3K]

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Step-by-step explanation:

3 0
2 years ago
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Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

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