Answer:
The location of the point is between Quadrant II and Quadrant III
Step-by-step explanation:
we know that
The abscissa refers to the x-axis and ordinate refers to the y-axis
so
in this problem we have
the coordinates of the point are 
see the attached figure to better understand the problem
The location of the point is between Quadrant II and Quadrant III
Answer:
161.8cm²
Step-by-step explanation:
solve for height which is the opposite
opp=x
sin(theata)= opp./hyp.
sin23=x/30
x=30×sin23
x=11.72cm
height=opposite
height=11.72cm
base=adjacent
base=27.6cm
½of 27.6cm=13.8
13.8cm×11.72cm=161.74 (2d.p)
161.74 rounded to the nearest tenths= 161.7
I'm not sure if it's the answer but it's the closest thing to the options
The answer is 3.16 ft
The surface area (SA) of the rectangular prism is:
SA = 2lw + 2ld + 2wd
However, the pool is without the top side, so the area of the top side should be excluded from the surface area of the pool. The surface area of the rectangular pool is:
SA = lw + 2ld + 2wd
We know:
SA = 210 ft²
l = 9 ft
w = 10 ft
d = ?
210 = 9 * 10 + 2 * 9 * d + 2 * 10 * d
210 = 90 + 18d + 20d
210 - 90 = 38d
120 = 38d
d = 120/38
d = 3.16 ft
1:1, because there’s a same number of both !
