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ziro4ka [17]
3 years ago
13

Help it's science so help

Chemistry
1 answer:
bija089 [108]3 years ago
7 0
1.b
2.b
3.a
 3 was the the opposite of the scenario stated   

 
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How did the ancient greek understanding of atomic particles likley influence dalton research?
GalinKa [24]

Answer:

The Greeks called these particles atomos, meaning indivisible, and the modern word “atom” is derived from this term. Democritus proposed that different types and combinations of these particles were responsible for the various forms of matter.

Explanation:

hope it helps

7 0
3 years ago
Read 2 more answers
Classify the reaction: N2 (g) + 3H2 (g) à 2NH3 (g)
Whitepunk [10]
For the reaction N2(g) + 3H2(g) <=> 2NH3(g),
we have two reactants combining to form a single product. This type of reaction is called a Synthesis reaction.

(Quick side note): Because this is a reversible, you could write it in the opposite direction as a decomposition reaction.
4 0
3 years ago
Which of the following descriptions
tangare [24]

Answer:

D

Explanation:

depending on the solid the shape will not change.

3 0
3 years ago
Stainless steel is an alloy of iron containing 5 percent nickel and 0.175 percent chromium. How many atoms of nickel are present
erica [24]
First you need to work out what mass of 84g of stainless steel is nickel, and because there's 5% you can simply divide by 20, giving 4.2g

For this you can use the equation Moles= \frac{Mass}{Mr}

The mass, as was worked out previously, is 4.2g
The Mr, which is found on the periodic table, is 28

Moles = \frac{4.2}{28} = 0.15mol

1mol = 6.023 x 10^{23} atoms

So, 0.15mol = 0.15 x 6.023 x 10^{23} = 9.0345 x 10^{22} atoms


3 0
3 years ago
Read 2 more answers
What is the volume of 0.250 m hydrochloric acid required to react completely with 20.0 ml of 0.250 m ca(oh)2?
Soloha48 [4]
The balanced equation for the above neutralisation reaction is as follows;
Ca(OH)₂ + 2HCl ----> CaCl₂ + 2H₂O
Stoichiometry of Ca(OH)₂ to HCl is 1:2
number of Ca(OH)₂ moles reacted - 0.250 mol/L x 20.0 x 10⁻³ L = 5.00 x 10⁻³ mol
according to molar ratio of 1:2
number of HCl moles required = 2 x number of Ca(OH)₂ moles reacted
number of HCl moles = 5.00 x 10⁻³ x 2 = 10.0 x 10⁻³ mol
molarity of HCl solution - 0.250 M
there are 0.250 mol  in volume of 1 L
therefore 10.0 x 10⁻³ mol in - 10.0 x 10⁻³ mol  / 0.250 mol/L = 40.0 mL 
40.0 mL of 0.250 M HCl is required
5 0
3 years ago
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