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Drupady [299]
3 years ago
14

Please help... giving a lot of points and awarding brainliest.

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
8 0
Theoretical Yield of H2SO3: 31.2 g
Percent Yield: 67.4%

Theoretical Yield of C2H6: 6.50
Percent Yield: 88.7%

Theoretical Yield of HF: 3.84
Percent Yield: 71.4%
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Please help fast. I will give brainliest.
Sonbull [250]

Answer:39 min

Explanation:

5 0
2 years ago
Why was meteorology such a late developer compared to other branches of science?
Sedaia [141]

Answer:

Because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface

Explanation:

Hello,

In this case, meteorology is the branch of science studying the atmosphere in its weather processes and forecasting and it had a late development because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface. We cannot forget that even nowadays, it is very difficult to predict upcoming weathers with the 100 % assurance and with many days in advance.

Best regards.

3 0
3 years ago
The isomerization reaction, ch3nc → ch3cn, is first order and the rate constant is equal to 0.46 s-1 at 600 k. what is the conce
Harlamova29_29 [7]
According to this formula :
㏑[A] /[Ao] = - Kt 
when we have Ao = 0.3 m 
and K =0.46 s^-1
t = 20min = 0.2 x 60 =12 s
So by substitution :
㏑[A] / 0.3 = - 0.46 * 12
㏑[A] / 0.3 = - 5.52
by taking e^x for both side of the equation we can get [A]
∴[A] = 0.0012 mol dm^-3
6 0
3 years ago
What is the molarity of a 799 mL solution that contains 3.3 moles of NaNO3?
rusak2 [61]

Answer:   I think It might be 1 M???

Explanation:  Sorry I'm not in high school I put the wrong age

8 0
3 years ago
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint
diamong [38]

Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

6 0
3 years ago
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