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NikAS [45]
3 years ago
11

In a package of 40 skittles, 35% were red. How many were not red?

Mathematics
2 answers:
Lesechka [4]3 years ago
7 0

First you would take 35% of 40:

.35 * 40 = 14

That's how many skittles ARE RED. Now, subtract 14 from 40:

40 - 14 = 26

Hope this helps!

wel3 years ago
3 0
Answer:

40 skittles times the percent of red

40 * 0.35 = 14

We then take that then subtract that from the total.

40 - 14 = 26

26 skittles were red.

0.35 is equivalent to 35%

Leave a thanks or a brainliest if this helped.
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Can someone please answer this question please answer it correctly and please show work please help me I need it
I am Lyosha [343]

Answer:

the answer to this question is the number 8

5 0
3 years ago
A rectangular box is 32 cm wide and 36 cm high. If the surface area of the box is 4344 square​ centimeters, find the length of t
AnnZ [28]

To find the surface area, multiply length x width x height.

let "length" = l

l x 32 x 36 = 4344

Simplify

l x (32 x 36) = 4344

l x 1152 = 4344

Isolate the length. Divide 1152 from both sides

(l x 1152)/1152 = (4344)/1152

l = 4344/1152

l = 3.77 (rounded)

3.77 cm is your length.

hope this helps

8 0
3 years ago
Find the equation of the circle that is shifted 5 units to the left and 2 units down from the circle with the equation x^2+y^2=1
marysya [2.9K]
Shifting a circle results to changes in the coordinates of the circle. For instance, if the coordinates of the center of the circle is taken to be (0,0), the new coordinates will be [(0+5),(0+2)] after shifting. The equation of the circle will also change with the same margin.

That is, the new equation will be;
(5+x)^2+(2+y)^2 =19

Notice, only the coordinates changes.
6 0
3 years ago
The distance from Rodney's house to the park is 100 meters. If he walks to the park and back to his house, how far will he have
konstantin123 [22]

Answer:

c. 20,000cm

Step-by-step explanation:

from is house to the park is 100m

from the park back to his house is another 100m

100m+100m=200m

1m = 100cm

200m = xcm

cross multiply

xcm = 200×100

xcm= 20,000cm

3 0
3 years ago
A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

4 0
3 years ago
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