You have to use the combined gas law (P₁V₁/T₁=P₂V₂/T₂) and solve for P₂ to get P₂=P₁V₁T₂/T₁V₂.
You need to convert all of the temperature values into terms of Kelvin so -50°C turns into 223K and 102°C turns to 375K. After you make that conversion you can just plug in all of the values into the idea gas law and you should get P₂=228.5kpa.
I hope this helps. Let me know if anything is unclear.
Answer:
pH = 2.56
Explanation:
The Henderson-Hasselbalch equation relates the pH to the Ka and ratio of the conjugate acid-base pair as follows:
pH = pKa + log([A⁻]/[HA]) = -log(Ka) + log([A⁻]/[HA])
Substituting in the value gives:
pH = -log(1.77 x 10⁻⁴) + log((0.0065M) / (0.10M))
pH = 2.56
The composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
<h3>How to convert weight % to atom %?</h3>
The weight percentage of an element can be converted to atom percentage as follows:
- C(Zn) = C1A2 / (C2A1) + (C1A2) × 100
- C(Cu) = C2A1 / (C1A2) + (C2A1) × 100
Where;
- C1 = 30
- C2 = 70
- A1 = 65.4g/mol
- A2 = 63.55g/mol
- C(Zn) = {30*63.55} / (70*65.4) + (30*63.55) × 100
- C(Cu) = {70*65.4} / (30*63.55) + (70*65.4) × 100
- C(Zn) = 29.4 at %
- C(Cu) = 70.6 at %
Therefore, the composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
Learn more about atomic percent at: brainly.com/question/10018123
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Answer is: <span>A. 1 molecule with 10 atoms.
Every ball represent one atom in one molecule.
</span><span>The </span>ball and stick model<span> is a </span>molecular model<span> of a </span>chemical substance<span> that shows the </span>three-dimensional<span> position of the </span>atoms<span> and the </span>bonds between them. <span>The atoms have spherical shape and they are </span><span>connected with sticks (one, two or three, depends on bonds).</span>
