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Andrew [12]
3 years ago
9

Please help me ASAP PLEASE​

Chemistry
1 answer:
vodomira [7]3 years ago
3 0
24 cm^3 CO2 / 1 * 1 dcm^3 / 1000 cm^3 * 1 mol / 24 dcm^3 = 0.001 mol of CO3 is required
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How to prepared sodium chloride solution in the laboratory.​
Afina-wow [57]

hope it will help you

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hope it will helps

5 0
3 years ago
What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0
3 years ago
Use the graph to answer both parts of this question about these three minerals. Do not use calculations.
11111nata11111 [884]

Answer:

Mercury is the most dense whereas Titanium is the least dense.

Explanation:

Since Density = Mass / Volume, the slope of the line can immediately tell us its relative density between the metals.

6 0
3 years ago
Read 2 more answers
A water bath in a physical chemistry lab is 1.85m long, 0.810m wide and 0.740m deep. If it is filled to within 2.57 in from the
jenyasd209 [6]

Answer:

The volume of water in water bath is 1,011 Liters.

Explanation:

Length of the water bath, L = 1.85 m

Width of the water bath, W= 0.810  m

Height of the water bath ,H= 0.740 m

Height of the water in water bath, h= 0.740 m - 2.57 inches

1 m = 39.37 inch

= 0.740 m - \frac{2.57}{39.37} m = 0.6747 m

Volume of the water in bath = L × W × h

=1.85 m\times 0.810 m\times 0.6747 m=1.011 m^3

1 m^3=1000 L

1.011 m^3=1.011\times 1000 L=1,011 L

The volume of water in water bath is 1,011 Liters.

6 0
4 years ago
*pls hurry, will give brainlyest or whatever!!*
brilliants [131]

Answer:

all of the above. they all are chemical reactions

4 0
3 years ago
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