Answer:
O is an element and H2O2 is a compound.
Explanation:
O is a single element while H2O2 has 2 elements, which makes it a compound.
Answer:
time required to mow lawn is 1274.06 minutes
Explanation:
given data
average mow = 1400 square meters each hour
area = 320000 square feet
to find out
How many minutes will take to mow lawn
solution
we know that here 1 square feet is equal to 0.092903 square meter
so 320000 square feet will be = 0.09203 × 320000 = 29728.9728 square meter
so time required is express as
time required = 
time required = 
time required = 21.23 hours
so time required = 21.23 × 60 min = 1274.06
time required to mow lawn is 1274.06 minutes
Answer:
Gravitational potential energy of the astronaut will change by a greater amount on the earth
Explanation:
Gravitational potential energy is expressed by the formula;
GPE = mgh
This means that the gravitational potential energy is directly proportional to the gravity(g)
Now, from constant values, gravity of moon is 1.62 m/s² while gravity of the earth is 9.81 m/s².
This means that if we plug in the values of g on the earth and g on the moon, the potential energy on the earth would be greater than that of the moon
Thus, gravitational potential energy of the astronaut will change by a greater amount on the earth
Answer:
Gamma waves are transmitted by ...... body tissues with very little absorption
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Answer:
A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.
B. Veloctiy (Vb) = 1.66m/s
Explanation:
Given the following data
x(a) = 0.3m
x(b) = 0
q = 1.6×10^-19
Q = 24nc
r = 0.15m
Required: the motion of the electron and the velocity (Vb)
1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B
2. Potential energy and kinetic energy are given by
U(a) + K(a) = U(b) + K(b). . .1
Initial P.E and K.E are given as
U(a) = kQ/√x²(a) + a2
By substitution, we have
U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)
U(a) = -1.03×10^-16
Final P.E and K.E are given as
U(b) = KQ/√x²(b) + a2
By substitution, we have
U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²
U(b) = -2.3×10^16
3. By substitution into equation 1 becomes
-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2
V(b) = √2×1.27×10^-16/9.1×10^31
V(b) = 1.66×10^7m/s
