Answer:
Explanation:
Given:
Initial θ = 0 rad (from rest)
Final θ = 14.3 rad
Time, t = 5 s
B.
Angular velocity, w = dθ / dt
= (14.3 - 0)/5
= 2.86 rad/s
A.
Acceleration, ao = dw/dt
Initial angular velocity, wi = 0 rad/s (from rest)
Final angular velocity, wf = 2.86 rad/s
a = (2.86 - 0)/5
= 0.572 rad/s^2
Answer:
33.48 V
Explanation:
Parameters given:
Number of turns, N = 420
Magnetic field strength, B = 0.055 T
Area, A = 0.065 m²
Angular velocity, ω = 22.3 rad/s
EMF induced in a coil is given as:
EMF = -dΦ/dt
where Φ = magnetic flux
Magnetic flux, Φ, is given as:
Φ = B * N * A * cosωt
EMF = -d( B * N * A * cosωt) / dt
EMF = B * N * A * ω * sinωt
where ωt = 90°
Therefore:
EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°
EMF = 33.48 V
Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
The wire vibrates back and forth between the poles of the magnet.
The frequency of the vibration is the frequency of the AC supply.
Is the velocity constant? Is there any friction?
3 meters per second
then after 40 seconds it must 3*40 = 120 meters
120 meters or 0.12 km if you will
