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Ganezh [65]
4 years ago
9

Why is helium so difficult to liquefy?

Chemistry
1 answer:
Debora [2.8K]4 years ago
3 0
Helium is very difficult to liquify because it only exists in its liquid form at an extremely low temperature. This temperature is <span>low temperature of −269 °C (about 4 K or −452.2 °F). It is only possible to maintain liquid helium in a highly artificial environment where this low temperature can be created. </span>
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Cation and anion of Cr(CO3)3
Olin [163]
Chromium has a positive charge (it's a multivalent metal with multiple positive charges)

Carbonate has a negative charge (-2)

Chromium would be the cation, and carbonate would be the anion.  


4 0
3 years ago
Read 2 more answers
if you want to know the identity of an unknown substance, what type of formula would you most likely want to know?
Leto [7]

Answer:

Smell: Most chemists can identify solvents by their distinctive smells (though this is a pretty bad idea). ¹

Melting point: If you've got very pure crystals, you can use their melting point to figure out which of several possible chemicals you've got.

Explanation:

I hope this helps and pls mark me brainliest :)

7 0
3 years ago
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A graduated cylinder with water has a mass of 534.26 g. The graduated cylinder itself has a mass of 214.36 g. What is the mass o
Alexxandr [17]

Answer: 319.9g

Explanation:

Mass of graduated cylinder with water = 534.26g

Mass of  graduated cylinder = 214.36g

Mass of just water = Mass of graduated cylinder with water - Mass of graduated cylinder.

Mass of just water = 534.26g  -  214.36 g =  319.9g

8 0
4 years ago
Calculate the number of atoms in 0.377 grams of ar
Advocard [28]
Molar mass Argon ( Ar ) = 39.95  g/mol

39.95 g ---------------- 6.02 x 10²³ atoms
0.377 g ---------------- ( atoms Ar )

( atoms Ar ) = 0.377 x ( 6.02 x 10²³ ) / 39.95

( atoms Ar ) = 2.26954 x 10²³ / 39.95

= 5.68 x 10²¹ atoms Ar

hope this helps!
5 0
4 years ago
How many grams of Al are needed to react with 63.0 g of FeO
Tema [17]

The amount of Al required will be 15.77 grams

<h3>Stoichiometric problem</h3>

First, the equation of the reaction:

2Al +3 FeO -- > Al_2O_3 + 3Fe

The mole ratio is 2:3.

Mole of 63.0 g of FeO = 63/71.84 = 0.8769 moles

Equivalent moles of Al = 0.8769 x 2/3 = 0.5846 moles

Mass of 0.5846 moles Al = 0.5846 x 26.98 = 15.77 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

4 0
2 years ago
Read 2 more answers
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