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Nikolay [14]
3 years ago
11

A simple pendulum, 1.00 m in length, is released from rest when the support string is at an angle of 35.0 from the vertical. Wh

at is the speed of the suspended mass at the bottom of the swing? (g = 9.80 m/s2 and ignore air resistance)
Physics
1 answer:
taurus [48]3 years ago
7 0

Answer:

Explanation:

Length = 1.00 m

If the length is 1.0, the vertical distance pivot to bob is cos 35 = 0.819

At the lowest point, vertical distance is 1.0, so the change is the difference, 0.181 meter

The potential energy of that height is converted to kinetic energy of motion, which determines the speed.

PE = KE

mgh = ½mV²

V = √(2gh) = 1.88 m/s

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What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

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8 0
2 years ago
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a=0.555m/s^2

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(0-18^2)/(2*291.9)=a

a=0.555m/s^2

8 0
3 years ago
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