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3 years ago

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A simple pendulum, 1.00 m in length, is released from rest when the support string is at an angle of 35.0 from the vertical. Wh

at is the speed of the suspended mass at the bottom of the swing? (g = 9.80 m/s2 and ignore air resistance)

1 answer:

taurus [48]3 years ago

7 0

Answer:

Explanation:

Length = 1.00 m

If the length is 1.0, the vertical distance pivot to bob is cos 35 = 0.819

At the lowest point, vertical distance is 1.0, so the change is the difference, 0.181 meter

The potential energy of that height is converted to kinetic energy of motion, which determines the speed.

PE = KE

mgh = ½mV²

V = √(2gh) = 1.88 m/s

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A ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. The plane of the circle is 1.00 m abov

Mamont248 [21]

Answer:

radial acceleration is 41.8 m / s²

Explanation:

The acceleration for circular motion is

a = v² / r

They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations

x = vox t

y = v₀ₓ t - ½ g t2

Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)

x = v₀ₓ t

t = x / v₀ₓ

y = - ½ g t²

Let's replace and calculate the initial velocity on the X axis

y = - ½ g (x / vox)²

v₀ₓ = √ (g x² / 2 y)

v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]

v₀ₓ = 3.54 m / s

This is the horizontal velocity, but since it circle is in horizontal position it is also the velocity of the body at the point of rupture.

Now we can calculate the radial acceleration

a = v² / r

a = 3.54² / 0.300

a = 41.8 m / s²

5 0

3 years ago

An object is at x = 0 at t = 0 and moves along the x axis according to the velocity–time graph in Figure P2.50.(a) What is the o

bezimeni [28]

Picture? I may be able to answer if you have a chart or some kind of graph as a referral to the question

8 0

3 years ago

A distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 n

maksim [4K]

Answer:

A) receding from the earth

B) $3.078x10^6m/s$

Explanation:

A) receding from the earth

The wavelength went from 434.1nm to 438.6nm, there was an increase in wavelength (also knowecn as redshift due to the doppler efft), this increase is due to the fact that the source that emits the radiation (the distant galaxy) is moving away and therefore the light waves it emits are "stretched", causing us to see a wavelength greater than the original.

B) $3.078x10^6m/s$

to calculate the relative speed we use the following formula:

$v_{rel}=c(1-\frac{\lambda_{1}}{\lambda_{2}} )$

where $c$ is the speed of light: $c=3x10^8m/s$

$\lambda_{1}$ is the wavelength emited by the source, and

$\lambda_{2}$ is the wavelength measured on earth.

we substitute all the values and do the calculations:

$v_{rel}=(3x10^8m/s)(1-\frac{434.1nm}{438.6nm} )\\\\v_{rel}=(3x10^8m/s)(1-0.98974)\\\\v_{rel}=(3x10^8m/s)(0.01026)\\\\v_{rel}=3.078x10^6m/s$

the relative speed is: $3.078x10^6m/s$

5 0

3 years ago

Please help,it is urgent!)

Romashka [77]

Answer:

answer is 18.58 because

5 0

2 years ago

Read 2 more answers

A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk

malfutka [58]

Answer:

The mass of the cargo is $M = 188.43 \ kg$

Explanation:

From the question we are told that

The radius of the spherical balloon is $r = 7.40 \ m$

The mass of the balloon is $m = 990\ kg$

The volume of the spherical balloon is mathematically represented as

$V = \frac{4}{3} * \pi r^3$

substituting values

$V = \frac{4}{3} * 3.142 *(7.40)^3$

$V = 1697.6 \ m^3$

The total mass the balloon can lift is mathematically represented as

$m = V (\rho_h - \rho_a)$

where $\rho_h$ is the density of helium with a value of

$\rho_h = 0.179 \ kg /m^3$

and $\rho_a$ is the density of air with a value of

$\rho_ a = 1.29 \ kg / m^3$

substituting values

$m = 1697.6 ( 1.29 - 0.179)$

$m = 1886.0 \ kg$

Now the mass of the cargo is mathematically evaluated as

$M = 1886.0 - 1697.6$

$M = 188.43 \ kg$

5 0

3 years ago