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Anestetic [448]
3 years ago
15

Application - You have two objects that you want to push the same distance (5 meters) across the floor. The objects have differe

nt masses. The first object is a dresser (40 kg) and the second object is a kitchen chair (11.5 kg). Which object will take more force to push the the 5 meters across the floor? Why?
Physics
1 answer:
Mamont248 [21]3 years ago
8 0

I see you're in Middle School, so I've got a hunch that they want you
to say "the dresser because it has more mass".  But that's a poor
answer, to a poor question.

The fact is that there's no way to tell.

The force it takes to move either object across the floor does NOT really
depend on just its mass.  It depends on both the object's mass AND the
friction between the object and the floor.  And THAT depends on the shape
of the feet where they touch the floor, and what kind of material the feet and
the floor are made of.

So it seems to me that we really don't have enough information to answer
the question with.

But again, I suspect that the answer they want is "the dresser because
it has more mass".

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a dog pulls on a pillow with a force of 8.4 N at an angle of 31 degrees above the horizontal. what is the x component of this fo
Natasha_Volkova [10]
The x component of the force is 8.4N * cos(31°) = 7.2N (2 s.f.)
4 0
4 years ago
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

7 0
3 years ago
A 0.850 kg mass is placed on a
densk [106]

Answer:

Picture

Explanation:

I am trying to solve this Q

but not sure if this a correct answer

or not.

Hope this helps.

5 0
3 years ago
When does a object exerts an action force
nlexa [21]

Answer: According to Newton's third law of motion, whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object. These two forces are called action and reaction forces.

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8 0
3 years ago
A bicycle tire contains 2.00 L of gas at an absolute pressure of 7.00 × 10 5 N/m 2 and a temperature of 18.0 °C . What will its
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Answer:

The final pressure will be 6.99 N/m^ 2

Explanation:

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Initial temperature of tire 31 °C

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Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)

pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2

New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2

= 6.99 N/m^ 2

4 0
4 years ago
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