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Anestetic [448]
3 years ago
15

Application - You have two objects that you want to push the same distance (5 meters) across the floor. The objects have differe

nt masses. The first object is a dresser (40 kg) and the second object is a kitchen chair (11.5 kg). Which object will take more force to push the the 5 meters across the floor? Why?
Physics
1 answer:
Mamont248 [21]3 years ago
8 0

I see you're in Middle School, so I've got a hunch that they want you
to say "the dresser because it has more mass".  But that's a poor
answer, to a poor question.

The fact is that there's no way to tell.

The force it takes to move either object across the floor does NOT really
depend on just its mass.  It depends on both the object's mass AND the
friction between the object and the floor.  And THAT depends on the shape
of the feet where they touch the floor, and what kind of material the feet and
the floor are made of.

So it seems to me that we really don't have enough information to answer
the question with.

But again, I suspect that the answer they want is "the dresser because
it has more mass".

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Answer:

360 ÷ 4 = 90

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A 360° circle is cut into 4 peaces in the form of + or × . It's one side is called 90°

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3 years ago
The force an ideal spring exerts on an object is given by Fx = -kx, where x measures the displacement of the object from its equ
shusha [124]

Answer:

The work done by this force can be found via the following formula

W = \int{F(x)} \, dx = \int\limits^0_{-20} {(-kx)} \, dx = \frac{-kx^2}{2}\left \{ {{x=0} \atop {x=-20}} \right. = \frac{-60*(-20)^2}{2} \\W = -12000J

Explanation:

Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

U = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2 =0 - \frac{1}{2}60(-20)^2 = -12000J

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A car travels at a velocity of 8m/s for 16s . How far did it travel?
sertanlavr [38]

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3 years ago
Water, with a density of 1000 kg/m3, flows out of a spigot, through a hose, and out a nozzle into the air. The hose has an inner
stepan [7]

Answer:

   P₁ = 2.3506 10⁵ Pa

Explanation:

For this exercise we use Bernoulli's equation and continuity, where point 1 is in the hose and point 2 in the nozzle

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

          A₁ v₁ = A₂ v₂

Let's look for the areas

          r₁ = d₁ / 2 = 2.25 / 2 = 1,125 cm

          r₂ = d₂ / 2 = 0.2 / 2 = 0.100 cm

          A₁ = π r₁²

          A₁ = π 1.125²

          A₁ = 3,976 cm²

          A₂ = π r₂²

          A₂ = π 0.1²

          A₂ = 0.0452 cm²

Now with the continuity equation we can look for the speed of water inside the hose

           v₁ = v₂ A₂ / A₁

           v₁ = 11.2 0.0452 / 3.976

           v₁ = 0.1273 m / s

Now we can use Bernoulli's equation, pa pressure at the nozzle is the air pressure (P₂ = Patm) the hose must be on the floor so the height is zero (y₁ = 0)

           P₁ + ½ ρ v₁² = Patm + ½ ρ v₂² + ρ g y₂

          P₁ = Patm + ½ ρ (v₂² - v₁²) + ρ g y₂

Let's calculate

           P₁ = 1.013 10⁵ + ½ 1000 (11.2² - 0.1273²) + 1000 9.8 7.25

           P₁ = 1.013 10⁵ + 6.271 10⁴ + 7.105 10⁴

           P₁ = 2.3506 10⁵ Pa

7 0
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5 ways to communicate better

Prepare yourself on the subject. ...

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Keep it simple. ...

Listen to others with intent. ...

Engage well.

For an individual to succeed as well as for an organization to succeed, effective communication is crucial. Leaders who can articulate their ideas well are better at motivating and forming bonds with their staff. Furthermore, it's critical to positively and concisely convey your opinions.Whether or not communication is successful determines whether a relationship will succeed. Being able to explain your ideas clearly is only one aspect of effective communication; listening intently is another. It is the capacity to completely comprehend, to demonstrate empathy, and to provide feedback in light of the other person's answer. Simply said, it is the fruitful interchange of ideas and opinions between individuals or organizations.

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