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BabaBlast [244]

3 years ago

5

A 20-kg child is tossed up into the air by her parent. the child is 2 meters off ground traveling 5 m/s.

1 answer:

julsineya [31]3 years ago

8 0

BOTH.

m=20kg v=5m/s h=2m g=9.8

GPE = mgh = 20*9.8*2 = 392 J

KE = 1/2*mv^2 = 1/2*20*5^2 = 250J

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What are the 3 Newton's law of motions?

irinina [24]

Answer:

laws of motion relate an object’s motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

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2 years ago

A thin walled spherical shell is rolling on a surface. What

ExtremeBDS [4]

Answer:

$=\frac{1/3}{5/6} = 0.4$

Explanation:

Moment of inertia of given shell $= \frac{2}{3} MR^2$

where

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R -sphere radius

we know linear speed is given as $v = r\omega$

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$K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

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8 0

3 years ago

Given the distance between the crest of one wave and the crest of the next wave, you can determine the?

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3 0

2 years ago

If the charge on the negative plate of the capacitor is 121 nano-Coulomb, how many excess electrons are on that plate? Write you

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Answer:

n = 756.25 giga electrons

Explanation:

It is given that,

If the charge on the negative plate of the capacitor, $Q=121\ nC=121\times 10^{-9}\ C$

Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

$Q=ne$

e is the charge on electron

$n=\dfrac{Q}{e}$

$n=\dfrac{121\times 10^{-9}}{1.6\times 10^{-19}}$

$n=7.5625\times 10^{11}$

or

n = 756.25 giga electrons

So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.

6 0

3 years ago