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BabaBlast [244]
3 years ago
5

A 20-kg child is tossed up into the air by her parent. the child is 2 meters off ground traveling 5 m/s.

Physics
1 answer:
julsineya [31]3 years ago
8 0

BOTH.

m=20kg      v=5m/s      h=2m     g=9.8

GPE = mgh = 20*9.8*2 = 392 J

KE = 1/2*mv^2 = 1/2*20*5^2 = 250J

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Considering the definition of kinetic energy, the bullet has a kinetic energy of 156.25 J.

<h3>Kinetic energy</h3>

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and in a rest position, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its rest state by applying a force to it.

The kinetic energy is represented by the following expression:

Ec= ½ mv²

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<h3>Kinetic energy of a bullet</h3>

In this case, you know:

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Replacing in the definition of kinetic energy:

Ec= ½ ×0.500 kg× (25 m/s)²

Solving:

<u><em>Ec= 156.25 J</em></u>

Finally, the bullet has a kinetic energy of 156.25 J.

Learn more about kinetic energy:

brainly.com/question/25959744

brainly.com/question/14028892

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