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3 years ago

Which of the following objects is usually the smallest?

Physics

2 answers:

Stels [109]3 years ago

8 0

I would say comet is the smallest and the sun is the biggest

Deffense [45]3 years ago

3 0

b. comets

Although comets appear very large when they are near the Sun because of the large dust cloud that follows behind them, they are actually the smallest of the objects listed.

Comets typically have a diameter of less than 6 miles, which is much smaller than the typical diameter of the other objects listed above.

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A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa

NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

$mV_1+3mV_2=(m+3m)V_f=4mV_f$

$V_1+3V_2=4V_f$ and making $V_f$ the subject then

$V_f=\frac {V_1+3V_2}{4}$ and since $V_1$ is initial velocity of car, value given as 4 m/s, $V_2$ is the initial velocity of the three cars stuck together, value given as 2 m/s and $v_f$ is the final velocity which is unknown. By substitution

$V_f=\frac {4+(3\times2)}{4}=2.5 m/s$

(b)

Initial kinetic energy is given by

$\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ$

Final kinetic energy is given by

$\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ$

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

6 0

3 years ago

Read 2 more answers

Which phrase best describes the time period in which the current body of scientific knowledge was developed? A. Just over the la

LiRa [457]

Answer:

The correct option is;

B. Throughout all of history

Explanation:

A body of knowledge comprises of a given collection of concepts, activities and terms that represents a professional discipline that is outlined by the associated scholarly society, therefore, scientific knowledge, being comprised of very diverse field of knowledge, with different approaches and changing understanding is taking as a process of learning about the universe data collection, experimenting analysis and communication with a theme of systems, equilibrium, models and constant change which makes the basis of the body of scientific knowledge to be throughout all of history.

3 0

2 years ago

If you see ##### in a cell, you should

Sveta_85 [38]

Answer:

it's D. Make the column wider

Explanation:

5 0

3 years ago

As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes

Mariulka [41]

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = $\frac{1}{3}c$ in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = $-\frac{1}{2}c$ with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = $\frac{1}{3}c-(-\frac{1}{2}c)$

u' = $\frac{1}{3}c+\frac{1}{2}c$

u' = $\frac{5}{6}c$

since this velocity ( $\frac{5}{6}c$ ) is greater than the ( $\frac{3}{4}c$ )

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

on substituting the values we get

$u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}$

$u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}$

$u'=\frac{5}{7}c$

since,

$u'=\frac{5}{7}c$ is less than ( $\frac{3}{4}c$ ), this means that the bullet will not hit

7 0

3 years ago

An astronaut is said to be weightless when they travel in the satellite. What does this mean?

Dovator [93]

Answer:

The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. The only force that acts upon humans in space is the force of gravity, which acts at a distance; but as there is no counter-force, we do not experience the sensation of weight over there.

6 0

2 years ago