Mass of CO₂ evolved : 0.108 g
<h3>Further explanation</h3>
Given
1.205g sample, 36% MgCO3 and 44% K2CO3
Required
mass of CO2
Solution
0.36 x 1.205 g=0.4338 g
mass C in MgCO₃(MW MgCO₃=84 g/mol, Ar C = 12/gmol)
= (12/84) x 0.4338
= 0.062 g
0.44 x 1.205 g = 0.5302 g
Mass C in K₂CO₃(MW=138 g/mol) :
= (12/138) x 0.5302
= 0.046 g
Total mass Of CO₂ :
= 0.062 + 0.046
= 0.108 g
Option “A” is the crest of the wave because it’s the maximum value of upward displacement within a cycle.
A)3 bcuz paper filters are used to separate solids from liquids
b) 2 bcuz it is a process of separating a pure liquid from a mixture of other liquids.And it works when it has different boiling point
1.strong acid: 2
2.weak acid:6
3.strong base:13
4.weak base:8
5.neutral:7
