Answer:
3.59x10⁻⁴ mol
Explanation:
Assuming ideal behaviour we can solve this problem by using the<em> PV=nRT formula</em>, where:
- R = 8314.46 Pa·L·mol⁻¹·K⁻¹
We<u> input the data given by the problem</u>:
- 205 Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K
And <u>solve for n</u>:
You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:
So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:
Carbon: 96.08g
Carbon = 49.48%
Nitrogen: 56.028g
Nitrogen = 28.85%
Oxygen: 31.998g
Oxygen = 16.48%
Answer:
The both compounds are different.
Explanation:
In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.
Given data:
For compound 1.
Mass of hydrogen = 15 g
Mass of oxygen = 120 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol
Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol
Total number of moles = 22.5 mol
% of hydrogen = 15 /22.5 × 100 = 66.7%
% of oxygen = 7.5 / 22.5× 100 = 33.3%
For compound 2:
Mass of hydrogen = 2 g
Mass of oxygen = 32 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol
Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol
Total number of moles = 4 mol
% of hydrogen = 2 /4 × 100 = 50%
% of oxygen = 2 / 4× 100 = 50%