How do you find the oxidation numbers for H3PO4
1 answer:
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Answer:
a) 5,3176x10⁻⁴ moles
b) 6,85x10⁻⁴ moles
c) The appropriate formula to calculate is Henderson-Hasselbalch.
d) pH = 4,86. Acidic solution but slighty
Explanation:
a) moles of acetic acid:
9,20x10⁻³L × 57,8x10⁻³M = <em>5,3176x10⁻⁴ moles</em>
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b) moles of sodium acetate:
56,2x10⁻³g ÷ 82,0 g/mole = <em>6,85x10⁻⁴ moles</em>
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c) The appropriate formula to calculate is Henderson-Hasselbalch:
pH= pka + log₁₀
d) pH= 4,75 + log₁₀
<em>pH = 4,86</em>
<em>3 < pH < 7→ Acidic solution but slighty</em>
I hope it helps!
<u>Answer:</u> The freezing point of solution is -0.09°C
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 120 kPa
i = Van't hoff factor = 1 (for non-electrolytes)
m = concentration of solute in terms of molality = ?
R = Gas constant =
T = temperature of the solution = 300 K
Putting values in above equation, we get:
- To calculate the depression in freezing point, we use the equation:
where,
i = Vant hoff factor = 1 (for non-electrolytes)
= molal freezing point depression constant = 1.86°C/m
m = molality of solution = 0.05 m
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
- The equation used to calculate freezing point of solution is:
where,
= Depression in freezing point = 0.09 °C
Freezing point of water = 0°C
Freezing point of solution = ?
Putting values in above equation, we get:
Hence, the freezing point of solution is -0.09°C