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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

guajiro [1.7K]3 years ago

3 0

A wave with a greater amplitude carries more energy to wherever it goes.

jarptica [38.1K]3 years ago

3 0

Answer: A wave with a greater amplitude will transfer more energy.

Explanation :

Wave is defined as the disturbance in any medium. Amplitude is one of the characteristics of a wave.

The maximum displacement traveled by the wave is termed as its amplitude. The energy that is carried by a wave depends on its amplitude. If the wave has a higher amplitude, then it will have higher energy and vice versa.

The attached figure shows the difference between high energy wave and low energy wave.

So, the correct option is (c) " more energy ".

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I’m a bit confused. What’s the question?

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3 years ago

How much time will it take for a bug to travel 5 meters across the floor if it is

Inessa05 [86]

Answer:

It will take 5 seconds

Explanation:

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3 years ago

En una fundición hay un horno eléctrico con capacidad para fundir totalmente 540 kg de cobre. Si la temperatura inicial del cobr

11Alexandr11 [23.1K]

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

$Q_1=mc(T_b-T_1)$ (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

$Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J$

Next, you calculate the energy required to melt the cooper by using the following formula:

$Q_2=mL_f$ (2)

Lf: melting constant of cooper = 134000J/kg

$Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J$

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

$Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ$

The total energy required is 2.95*10^5 kJ

3 0

3 years ago

How does a compound eye work?

Reil [10]

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8 0

2 years ago

The electric field strength between the plates of a simple air Capacitor is equal to the voltage across the plates divided by th

exis [7]

Answer:

$d=\frac{112\,V}{1100\,\frac{V}{cm}} \\d=\frac{28}{75} \,cm=0.101818.. \,cm$

Explanation:

Recall that the equation for the electric field intensity between the plates of a capacitor is given by:

$E=\frac{\Delta V}{d}$

where E is the electric field, $\Delta V$ is the voltage across the plate of the capacitor, and "d" is the separation (distance) between the capacitor's plates.

So we need to solve for the distance in the equation above, but also make sure that the units for electric field and potential difference are in agreement. We then write the electric field strength in V/cm :

1.1kV/cm = 1100 V/cm

Now in the equation:

$E=\frac{\Delta V}{d}\\1100\,\frac{V}{cm} =\frac{112\,V}{d\\}\\d=\frac{112\,V}{1100\,\frac{V}{cm}} \\d=\frac{112}{1100} \,cm\\d=\frac{28}{75} \,cm=0.101818.. \,cm$

5 0

3 years ago