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Leona [35]
3 years ago
11

a penny dropped into a wishing well reaches the bottom in 1.5 seconds. what was the velocity at impact? i did -9.8 X 1.5 and got

-14.7... is it negative or positive? because the acceleration due to gravity is -9.8... idk help please asap
Physics
1 answer:
nexus9112 [7]3 years ago
3 0

Before you ever start doing a problem that involves direction, YOU DECIDE
which direction you're going to call positive.

If you call UP the positive direction, then the force of gravity is a negative
force (it pulls down), the acceleration of gravity is a negative acceleration
(because it's in the direction of a negative force), and things that are falling
have negative velocity.

It's your decision.

The acceleration due to gravity and the force of gravity are in the same
direction.  If something falls out of your hand, OF COURSE it's going to
move in the same direction as the force on it.

========================================

Let's say you decided to call UP the positive direction.
Then the acceleration of gravity, and the force of gravity, are both negative.

Now you throw a rock straight UP.

-- Its velocity is positive.

-- But its acceleration is negative, so its velocity is going to keep shrinking,
less and less, until it becomes zero.  (Top of the rock's trip.)

-- Since the negative acceleration points down, it eventually conquers
the upward velocity, and the velocity begins to point down (negative).

-- Now the acceleration is in the same direction as the velocity (both
are negative), so the velocity starts growing, becoming more and more
negative, as the acceleration keeps adding speed to it.

What does all this mean ?

When you throw a rock straight up, it goes slower and slower,
strops rising at some point, starts falling, then gets faster and
faster as it falls.

Everybody knows this as soon as they get to be 2 or 3 years old.
But they don't think about it in negative and positive velocity and
acceleration, until they get to high school and learn the language 
of Physics.

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14. If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change
klio [65]

Lets se

And

\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}

\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}

So

\\ \rm\Rrightarrow k\propto m

If spring constant is doubled mass must be doubled

8 0
2 years ago
Please help!
andrew-mc [135]

Answer:

V=W/Q

107V= W/17C

= We= 107×17 J

= 1819 J

Explanation:

hope it helps

3 0
2 years ago
1) A person riding their bike on a nice cloudy day travels 50 meters in 20 seconds.
Rasek [7]

Answer:

5.59

Explanation:

50 meters in 10 seconds is 11.18, which is an easy way to remember. Just divided by 2

5 0
2 years ago
· A car moves at 12 m/s and coasts up a hill with a
Zigmanuir [339]

Explanation:

Given that,

Initial speed of a car, u = 12 m/s

Aceleration, a = -1.6 m/s²

(a) The displacement of car after 6 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 6+\dfrac{1}{2}\times (-1.6)\times 6^2\\\\d=43.2\ m

(b) The displacement of the car after 9 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 9+\dfrac{1}{2}\times (-1.6)\times 9^2\\\\d=43.2\ m

Hence, this is the required solution.

7 0
3 years ago
A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running
MrRissso [65]

The runner has initial velocity vector

\vec v_0=\left(2.88\dfrac{\rm m}{\rm s}\right)\,\vec\jmath

and acceleration vector

\vec a=\left(0.350\dfrac{\rm m}{\mathrm s^2}\right)(\cos(-52.0^\circ)\,\vec\imath+\sin(-52.0^\circ)\,\vec\jmath)

so that her velocity at time t is

\vec v=\vec v_0+\vec at

She runs directly east when the vertical component of \vec v is 0:

2.88\dfrac{\rm m}{\rm s}+\left(0.350\,\dfrac{\rm m}{\mathrm s^2}\right)\sin(-52.0^\circ)\,t=0\implies t=10.4\,\rm s

It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time t would be

\vec x=\vec v_0t+\dfrac12\vec at^2

so that after 10.4 s, her position would be

\vec x=(10.1\,\mathrm m)\,\vec\imath+(17.2\,\mathrm m)\,\vec\jmath

which is 19.9 m away from her starting position.

8 0
3 years ago
Read 2 more answers
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