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Leona [35]
3 years ago
11

a penny dropped into a wishing well reaches the bottom in 1.5 seconds. what was the velocity at impact? i did -9.8 X 1.5 and got

-14.7... is it negative or positive? because the acceleration due to gravity is -9.8... idk help please asap
Physics
1 answer:
nexus9112 [7]3 years ago
3 0

Before you ever start doing a problem that involves direction, YOU DECIDE
which direction you're going to call positive.

If you call UP the positive direction, then the force of gravity is a negative
force (it pulls down), the acceleration of gravity is a negative acceleration
(because it's in the direction of a negative force), and things that are falling
have negative velocity.

It's your decision.

The acceleration due to gravity and the force of gravity are in the same
direction.  If something falls out of your hand, OF COURSE it's going to
move in the same direction as the force on it.

========================================

Let's say you decided to call UP the positive direction.
Then the acceleration of gravity, and the force of gravity, are both negative.

Now you throw a rock straight UP.

-- Its velocity is positive.

-- But its acceleration is negative, so its velocity is going to keep shrinking,
less and less, until it becomes zero.  (Top of the rock's trip.)

-- Since the negative acceleration points down, it eventually conquers
the upward velocity, and the velocity begins to point down (negative).

-- Now the acceleration is in the same direction as the velocity (both
are negative), so the velocity starts growing, becoming more and more
negative, as the acceleration keeps adding speed to it.

What does all this mean ?

When you throw a rock straight up, it goes slower and slower,
strops rising at some point, starts falling, then gets faster and
faster as it falls.

Everybody knows this as soon as they get to be 2 or 3 years old.
But they don't think about it in negative and positive velocity and
acceleration, until they get to high school and learn the language 
of Physics.

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A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal compon
Anettt [7]
First of all, let's write the equation of motions on both horizontal (x) and vertical (y) axis. It's a uniform motion on the x-axis, with constant speed v_x=30 m/s, and an accelerated motion on the y-axis, with initial speed v_y=20 m/s and acceleration g=9.81 m/s^2:
S_x(t)=v_xt
S_y(t)=v_y t- \frac{1}{2} gt^2
where the negative sign in front of g means the acceleration points towards negative direction of y-axis (downward).

To find the distance from the landing point, we should find first the time at which the projectile hits the ground. This can be found by requiring
S_y(t)=0
Therefore:
v_y t -  \frac{1}{2}gt^2=0
which has two solutions:
t=0 is the time of the beginning of the motion,
t= \frac{2 v_y}{g} = \frac{2\cdot 20 m/s}{9.81 m/s^2}=4.08 s is the time at which the projectile hits the ground.

Now, we can find the distance covered on the horizontal axis during this time, and this is the distance from launching to landing point:
S_x(4.08 s)=v_x t=(30 m/s)(4.08 s)=122.4 m
4 0
3 years ago
Your friend has slipped and fallen. To help her up, you pull with a force F, as the drawing shows. The vertical component of thi
sineoko [7]

This question can be solved using the concept of the composition of the vector.

(a) The magnitude of F is b "164.27 N".

(b) The angle of the vector from horizontal is " ".

(a)

From the composition of the rectangular components of a vector, we know that the magnitude of the resultant vector is given by the following formula:

F = \sqrt{F_x^2+F_y^2}

where,

F_x = x-component of the force = 122 N

F_y = y-component of the force = 110 N

Therefore,

F = \sqrt{(122\ N)^2+(110\ N)^2}

<u>F = 164.27 N</u>

(b)

The angle of the vector is given by the following formula:

\theta = tan^{-1}(\frac{F_y}{F_x})\\\\\theta = tan^{-1}(\frac{110\ N}{122\ N})\\\\

<u>θ = 42.04°</u>

Learn more about the composition of vector here:

brainly.com/question/24313520?referrer=searchResults

3 0
3 years ago
Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters above the surface.
Serhud [2]

Answer:

Correct answer:  E total = 2,800 J

Explanation:

Given:

m = 4 kg   the mass of the object

V = 20 m/s  the speed (velocity) of the object

H = 50 m the height of the object above the surface

E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

Ep = m g H   we take g = 10 m/s²

Ep = 4 · 10 · 50 = 2,000 J

Ek = m V² / 2

Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

God is with you!!!

4 0
3 years ago
What does energy give objects the ability to do?
Tasya [4]
Well, <span>according to the laws of physic energy can neither be created nor destroyed only transformed, this means that when for example gas burns the energy released is transformed into heat and forward momentum pushing the car forward.
I hope my answer helped you</span>
8 0
3 years ago
Which of the following is a compound machine
Ivahew [28]

The answer is c.

Hope this helps!!!!!!!!!!

8 0
4 years ago
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