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3 years ago

What term is used to describe the hot ash, gases, and materials being erupted at speeds of up to 400 mph?

1 answer:

fomenos3 years ago

7 0

The word 'magma' is used to refer to the hot ash, gases and material expelled by a volcano during an eruption. To be more precise, when all these materials reach the ground, the word 'lava' is also used.

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Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a

Jlenok [28]

Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

$P = \frac{F}{A}$

where,

P = Pressure exerted by the boy = ?

F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)

A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

Therefore,

$P = \frac{40\ N}{0.03\ m^2}\\\\$

4 0

3 years ago

Two Atoms are isotopes of each other if they have the same number of_______ but a different number _________.

zloy xaker [14]

The correct answer is #4. They have the same number of protons but a different number of neutrons.

4 0

2 years ago

Use your periodic table to answer the following question.

Pavel [41]

Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!

6 0

2 years ago

Which statement about the positive and negative value of speed compared to velocity is true?

mestny [16]

D is the answer
Velocity maybe negative or positive
while speed is always positive

3 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t

maw [93]

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=\frac{L-A}{2}$

where A = $\frac{Velocity ofthe sound (V)}{Frequency (F)}$

we have:

$L_1=\frac{L-\frac{V}{F} }{2}$

$L_1=\frac{6.69-\frac{343}{750} }{2}$

$L_1=\frac{6.69-0.457 }{2}$

$L_1=\frac{6.233 }{2}$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

3 0

3 years ago