All categories

3 years ago

What term is used to describe the hot ash, gases, and materials being erupted at speeds of up to 400 mph?

1 answer:

fomenos3 years ago

7 0

The word 'magma' is used to refer to the hot ash, gases and material expelled by a volcano during an eruption. To be more precise, when all these materials reach the ground, the word 'lava' is also used.

You might be interested in

Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a

Jlenok [28]

Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

$P = \frac{F}{A}$

where,

P = Pressure exerted by the boy = ?

F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)

A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

Therefore,

$P = \frac{40\ N}{0.03\ m^2}\\\\$

4 0

2 years ago

Two Atoms are isotopes of each other if they have the same number of_______ but a different number _________.

zloy xaker [14]

The correct answer is #4. They have the same number of protons but a different number of neutrons.

4 0

2 years ago

Use your periodic table to answer the following question.

Pavel [41]

Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!

6 0

2 years ago

Which statement about the positive and negative value of speed compared to velocity is true?

mestny [16]

D is the answer
Velocity maybe negative or positive
while speed is always positive

3 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t

maw [93]

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=\frac{L-A}{2}$

where A = $\frac{Velocity ofthe sound (V)}{Frequency (F)}$

we have:

$L_1=\frac{L-\frac{V}{F} }{2}$

$L_1=\frac{6.69-\frac{343}{750} }{2}$

$L_1=\frac{6.69-0.457 }{2}$

$L_1=\frac{6.233 }{2}$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

3 0

3 years ago