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3 years ago

How do exons and introns differ?

1 answer:

7 0

Exons And Introns differ because Exons code for protein and Introns do not.

so your answer would be: Exons code for Proteins

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You might be interested in

Which of these are some of the largest grazers in the tundra? (Select all that apply.)

PilotLPTM [1.2K]

Answer:

musk ox

caribou

Explanation:

6 0

2 years ago

Read 2 more answers

A solenoid having an inductance of 6.95 μh is connected in series with a 1.24 kω resistor. (a) if a 12.0 v battery is connected

Serggg [28]

In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is

Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms

The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
$I= \frac{V( 1- e^{-t/τ} )}{R}$ , where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
$7.12x 10^{-3} = \frac{12( 1- e^{-t/5.6x 10^{-9} } )}{1240}$

t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
$I= \frac{12( 1- e^{-1 } )}{1240}$

I = 6.12 mA

3 0

4 years ago

7. A car travels a certain distance with a speed of

goblinko [34]

Let distance be x.

Time in going, t 1 = x/50

Time in coming, t 2 = x/40

Total time T = x/40 +x/50 = 9x/200

Average speed = total distance/ total time

=( x+x)/(9x/200)= 2x ×200/9x = 400/9 = 44.44 km/h

5 0

3 years ago

We can reasonably model a 90-W incandescent lightbulb as a sphere 7.0cm in diameter. Typically, only about 5% of the energy goes

Ronch [10]

Answer:

292.3254055 W/m²

469.26267 V/m

$1.56421\times 10^{-6}\ T$

Explanation:

P = Power of bulb = 90 W

d = Diameter of bulb = 7 cm

r = Radius = $\frac{d}{2}=\frac{7}{2}=3.5\ cm$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

The intensity is given by

$I=\frac{P}{A}\\\Rightarrow I=\frac{90}{4\pi 0.035^2}\\\Rightarrow I=5846.50811\ W/m^2$

5% of this energy goes to the visible light so the intensity is

$I=0.05\times 5846.50811\\\Rightarrow I=292.3254055\ W/m^2$

The visible light intensity at the surface of the bulb is 292.3254055 W/m²

Energy density of the wave is

$u=\frac{1}{2}\epsilon_0E^2$

Energy density is also given by

$\frac{I}{c}=\frac{1}{2}\epsilon_0E^2\\\Rightarrow E=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E=\sqrt{\frac{2\times 292.3254055}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E=469.26267\ V/m$