Answer:
1065 Kgm-3
Explanation:
We can determine the relative density of the athlete from the formula;
Relative density of athlete = weight of athlete in air/upthrust on athlete
Since weight of athlete in air= 690 N
Weight of athlete in water = 42 N
Upthrust on athlete= weight in air - weight in water
Upthrust on athlete= 690 N - 42 N = 648 N
Relative density of athlete= 690 N / 648 N
Relative density of athlete= 1.065
Therefore, average density of the athlete= relative density × density of water = 1.065 × 1000 Kgm-3 = 1065 Kgm-3
It would have to be a solid so the answer would be A.
Answer:
= 0.7 A, = 1.3 A and ε = 7.4 V
Explanation:
From the given circuit, applying Kirchhoff's rule;
Ammeter reading, = 2 A
⇒ = + = 2 A
Dividing the circuit to loops 1 and 2.
a. From loop 1,
15 + 7 - 5 = 0
15 + 7 - 10 = 0 (since = 2 A)
7 - 5 = 0
= 0.7 A
But, = +
⇒ 2 = 0.7 +
= 1.3 A
b. From loop 2,
ε + 2 - 5 = 0
ε + 2 - 10 = 0
ε + 2.6 - 10 = 0
ε - 7.4 = 0
ε = 7.4 V
Therefore, = 0.7 A, = 1.3 A and ε = 7.4 V.