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Papessa [141]
3 years ago
15

a roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceler

ation
Physics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

vi=6m/s

vf=70 m/s

t=4s

a=vf-vi/t=16m/s2

Explanation:

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Seberkas cahaya monokromatik dijatuhkan pada kisi difraksi dengan 5000 goresan/cm menghasilkan spectrum garis terang orde kedua
Vlada [557]

Answer:

500 nm

Explanation:

In this problem, we have a diffraction pattern created by light passing through a diffraction grating.

The formula to find a maximum in the pattern produced by a diffraction grating is the following:

d sin \theta = m\lambda

where:

d is the distance between the lines in the grating

\theta is the angle at which the maximum is located

m is the order of the maximum

\lambda is the wavelength of the light used

In this problem we have:

\theta=30^{\circ} is the angle at which is located the 2nd-order bright line, which is the 2nd maximum

n = 5000 lines/cm is the number of lines per centimetre, so the distance between two lines is

d=\frac{1}{d}=\frac{1}{5000}=2\cdot 10^{-4} cm = 2\cdot 10^{-6} m

Re-arranging the equation for \lambda, we find the wavelength of the light used:

\lambda=\frac{d sin \theta}{m}=\frac{(2\cdot 10^{-6})(sin 30^{\circ})}{2}=5\cdot 10^{-7} m = 500 nm

4 0
3 years ago
What are Earth's mineral resources and how long might<br> reserves last?
amm1812
Reserves might last 53.3 years.

Earth’s mineral resources:

3 0
3 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
Alik [6]

1) Acceleration of the sled

The acceleration of the sled is given by the net force acting in the direction parallel to the incline. There are two forces acting along this direction: the component of the weight parallel to the ramp (downward) and the friction (upward). Therefore, the net force acting in this direction is

F=mg sin \theta- F_f =(8 kg)(9.8 m/s^2)(sin 50^{\circ})-2.4 N=57.7 N

And the acceleration is given by Newton's second law:

a=\frac{F}{m}=\frac{57.7 N}{8 kg}=7.21 m/s^2


2) Normal force

The normal force acting on the sled is equal to the component of the weight perpendicular to the incline, therefore:

N=mg cos \theta=(8 kg)(9.8 m/s^2 )(cos 50^{\circ})=50.4 N

5 0
3 years ago
Read 2 more answers
When a researcher wants to correlate tension with depression, she develops tests that measure these two emotional states. The te
Igoryamba

Answer:

The answer is: measuring instrument

Explanation:

The researcher develops test to measure the variables she is interested in. So, they are her measuring instrument.

8 0
3 years ago
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A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that numerically e
Neko [114]

Answer:

the time at which it passes through the equilibrum position is:

t = 0.1 second

Explanation:

given

w= 4pounds

k(spring constant) = 2lb/ft

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β(initial point above equilibrum) = 1

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attached is an image showing the calculations, because some of the parameters aren't convenient to type.

3 0
3 years ago
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