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Semmy [17]
2 years ago
14

A student attaches a block of mass M to a vertical spring so that the block-spring system will oscillate if the block-spring sys

tem is released from rest at a vertical position that is not the system’s equilibrium position. The figure shows three positions of the spring as it travels from point X to point Y and then from point Y to point Z . Point X is the lowest point of the center of mass of the block as it oscillates. Point Y is the equilibrium position of the block-spring system. Point Z is the highest point of the center of mass of the block as it oscillates. The gravitational potential energy of the block-spring-Earth system is considered to be zero at point X . Which of the following claims is correct about the block-spring-Earth system?
A) The gravitational potential energy of the block-spring-Earth system is the same at point X as it is at point Z .
B) The spring potential energy of the block-spring-Earth system is the same at point X as it is at point Z .
C) The block-spring-Earth system does not have spring potential energy at point Y. D) The block-spring-Earth system has minimum potential energy at point Y .
Please give a detailed explanation.
Physics
1 answer:
Vlada [557]2 years ago
7 0
WAAAAAAAAAAAAAAAAAAAAAAAAARRRRR
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3. A moving<br> car covers a distance of 100 km in two hours.<br> What is meant by this?
GenaCL600 [577]

Answer:

50km /hour

Explanation:

The car moves 100km in two hours.

We can write a ratio like this:

100km : 2hr

Divide both sides by two and you get:

50km : 1hr

Meaning the moving car is moving 50km an hour.

Hope this helps :)

8 0
2 years ago
A bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27 s. What is the angular acceleration of the tires?
Nimfa-mama [501]

The angular acceleration of a bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27 s will be 2. 57 rad/s²

<h3>What is angular acceleration?</h3>

Angular acceleration can be defined as the time it takes for a change in angular velocity. It is denoted as 'α' with a unit of rads/s²

It is expressed thus;

α= Δω ÷ Δt

Where α = angular acceleration

Δw = change in angular velocity = velocity ÷ radius

Δ t = change in time

<h3>How to calculate the angular acceleration</h3>

Using the formula:

α= Δω ÷ Δt

v = 5. 33m/s, r = 0. 33m and t = 6.27s

Substitute the values to get the angular velocity

Δw = v÷ r = 5. 33 ÷ 0.330 = 16. 15 m/s

Substitute the value of Δw into the equation

α= Δω ÷ Δt = 16. 15 ÷ 6. 27 = 2. 57 rad/s²

Therefore, the angular acceleration of a bike with tires radius of 0. 330m, speed of 5. 33mls in 6. 27s is 2. 57 rad/s²

Learn more about angular acceleration here:

brainly.com/question/21278452

#SPJ1

8 0
1 year ago
Helpppp me solve this
mash [69]

Answer:

a is the answer

Explanation:

6 0
3 years ago
Read 2 more answers
A student drops a rock from a bridge to the water 12m below. How many seconds does it take the rock to hit the water?
ANEK [815]
R = \frac{g t^{2} }{2}
r - displacement or height
t - time taken
g = 10 m/s-2
t = square root from 2r/g = \sqrt{ \frac{2 x 12}{10} } = 1.5 seconds
7 0
3 years ago
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
son4ous [18]

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

\Delta U =U_f - U_i =Q-W

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J

3 0
3 years ago
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