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Semmy [17]
3 years ago
14

A student attaches a block of mass M to a vertical spring so that the block-spring system will oscillate if the block-spring sys

tem is released from rest at a vertical position that is not the system’s equilibrium position. The figure shows three positions of the spring as it travels from point X to point Y and then from point Y to point Z . Point X is the lowest point of the center of mass of the block as it oscillates. Point Y is the equilibrium position of the block-spring system. Point Z is the highest point of the center of mass of the block as it oscillates. The gravitational potential energy of the block-spring-Earth system is considered to be zero at point X . Which of the following claims is correct about the block-spring-Earth system?
A) The gravitational potential energy of the block-spring-Earth system is the same at point X as it is at point Z .
B) The spring potential energy of the block-spring-Earth system is the same at point X as it is at point Z .
C) The block-spring-Earth system does not have spring potential energy at point Y. D) The block-spring-Earth system has minimum potential energy at point Y .
Please give a detailed explanation.
Physics
1 answer:
Vlada [557]3 years ago
7 0
WAAAAAAAAAAAAAAAAAAAAAAAAARRRRR
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"My distance to the center of the earth is about 4000 miles when I am on the surface. If I go to a height of 8000 miles above th
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Given,

Distance from the surface to the center of the earth, d=4000 miles

Distance from the center to you at a height of 8000 miles, a= 8000+4000=12000 miles

The gravitational force acting on a person at the surface is equal to his weight.

From Newton's Universal Law of Gravitation, the gravitational force is

F=\frac{G\times M\times m}{r^2}

Where G is the gravitational constant, M is the mass of the earth, m is the mass of the object/person, r is the distance between the center of the earth and the object/person

At the surface, this force is equal to the weight of the person, W=mg

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F_s=\frac{G\times M\times m}{d^2}=W

On substituting the of d,

W=\frac{\text{GMm}}{4000^2}

At a height of 8000 miles from the surface, the gravitational force is equal to,

F_a=\frac{GMm}{12000^2}

On dividing the above two equations,

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F_a=\frac{1}{9}W

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Learn more about conservation of energy here: brainly.com/question/166559

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