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Alisiya [41]
3 years ago
6

............................................................??????????????

Physics
1 answer:
den301095 [7]3 years ago
8 0

Answer:

I_{1} = 0.7 A, I_{2} = 1.3 A and ε = 7.4 V

Explanation:

From the given circuit, applying Kirchhoff's rule;

Ammeter reading, I_{0} = 2 A

⇒    I_{0} = I_{1} + I_{2} = 2 A

Dividing the circuit to loops 1 and 2.

a. From loop 1,

15 + 7I_{1} - 5I_{0} = 0

15 + 7I_{1} - 10 = 0    (since I_{0} = 2 A)

7I_{1} - 5 = 0

I_{1} = 0.7 A

But,  I_{0} = I_{1} + I_{2}

⇒      2 = 0.7 + I_{2}

        I_{2} = 1.3 A

b. From loop 2,

ε + 2I_{2} - 5I_{0} = 0

ε + 2I_{2} - 10 = 0

ε + 2.6 - 10 = 0

ε - 7.4 = 0

ε = 7.4 V

Therefore, I_{1} = 0.7 A, I_{2} = 1.3 A and ε = 7.4 V.

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