Answer:
Explanation:
Hello,
In this case, the first step is to compute the volume of the block considering the length, height and width:
Then, we compute the volume in cubic centimetres:
Finally, as the density is given by:
We solve for the mass:
Best regards.
Answer:
letter A.
Explanation:
the rate of a chemical reaction can be raised by increasing the surface area of a solid reactant. this is done by cutting the substance into small pieces, or by grinding it into a powder.if the surface area of a reactant is inceased: more particles are exposed to the other reactant.
HOPE IT HELPS(◍•ᴗ•◍)❤
The thing that two changes have in common that snails growing shells and rust forming on a bicycle frame is option D. Both are caused by cooling.
<h3>How come snails develop shells?</h3>
Calcium carbonate is said to be the material that makes up the shell. The snail's shell expands as it grows to accommodate its growing body. Snails and slugs are also members of the mollusc family of creatures.
Therefore, note that air that has been mixed with the metal can make rust to develop. and as such, option D. Both are caused by cooling. is correct.
Learn more about snails growing shells from
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See full question below
What do these two changes have in common? snails growing shells rust forming on a bicycle frame Select all that apply.
A. Both are only physical changes.
B. Both are caused by heating.
C. Both are chemical changes.
D. Both are caused by cooling
Stoichiometry <span>of the reaction:
</span><span>2 KClO</span>₃<span> = 2 KCl + 3 O</span>₂
↓ ↓
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?
KClO₃ = 2 * 3 / 2
KClO₃ = 6 / 2
= 3 moles de KClO₃
hope this helps!
When the concentration is expressed in ppm, that means parts per million. It is also equivalent to mg/L. For this problem, we do stoichiometric calculations. We manipulate the units by cancelling like units if they appear in the numerator and denominator side until we come with the amount of solid Ca(OCl)2 needed. The solution is as follows:
40 mg/L * (1 L/1000 mL) * 50 mL * (1 g/1000 mg) * (1 mol OCl⁻/51.452 g) * (1 mol Ca(OCl)₂/ 2 mol OCl⁻) * (142.983 g Ca(OCl)₂/mol) * 0.95 = 2.64×10⁻3 g or 2.64 mg.
Therefore, you would need 2.64 mg of solid Ca(OCl)₂.
