You must react 5.3 g H_2 to produce 47 g H_2O.
<em>Step 1</em>. Calculate the <em>moles of H_2O</em>
Moles of H_2O = 47 g H_2O × (1 mol H_2O/18.02 g H_2O) =2.61 mol H_2O
<em>Step 2</em>. Calculate the <em>moles of H_2
</em>
Moles of H_2 = 2.61 mol H_2O × (2mol H_2/2 mol H_2O) = 2.61 mol H_2
<em>Step 3</em>. Calculate the <em>mass of H_2</em>
Mass of H_2 = 2.61 mol H_2 × (2.016 g H_2/1 mol H_2) = 5.3 g H_2
A compound is a substance formed when two or more chemical elements are chemically bonded together. In mixtures, the substances present are not chemically bonded together.
Answer:
B
Explanation:
B
have cells with a cell wall and are heterotrophic
There are 67.2 liters of CO2 at STP
<h3>Further explanation</h3>
Given
3 mole of CO2
Required
Volume of CO2 at STP
Solution
Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So for 3 moles :
= 3 x 22.4 L
= 67.2 L
