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alukav5142 [94]
3 years ago
14

An aluminum can weighing 10 g absorbs 106.8 J of heat and warms by 12 degrees C. What is the specific heat of the aluminum can?

Use this scenario to answer questions 6 - 10.
Chemistry
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}

Explanation:

The heating process is modelled after the First Law of Thermodynamics:

Q = m \cdot c_{Al}\cdot \Delta T

The specific heat of the aluminium can is:

c_{Al} = \frac{Q}{m\cdot \Delta T}

c_{Al} = \frac{106.8\,J}{(10\,g)\cdot (12^{\circ}C)}

c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}

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