Question

15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 50. mL at 1.0 atm and 300. K (B) 50. mL at 0.5 atm and 300. K C) 100. mL at 0.5 atm and 300. K D) 100. mL at 1.0 atm and 300. K
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Answer 1

The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

What is the number of moles of gases in the given samples?

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

• P is pressure
• V is volume
• n is number of moles of gas
• T is temperature of gas
• R is molar gas constant = 0.082 atm.L/mol/K

Moles of gas in the given helium gas sample:

P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K

n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

n = 0.00203 moles

B. n =  0.5 * 0.05 / 0.082 * 300

n = 0.00102 moles

C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

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