<span>Answer:
We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees)
That means we heated it up 36.55 degrees
The formula to solve this is C = Q / M x dT
where
C is the specific heat of the liquid CFC (.91 J/G/C)
Q is the amount of heat required (what we're trying to find out)
M is the mass (52.5 grams)
and dT is the temperature difference (36.55 degrees)
Now put in the values and find out what Q is
.91 = Q / 52.5 x 36.55
.91 = Q / 1918.875
Q = 1746.17 joules to heat up the liquid CFC</span>
Answer: I think the answer is C
Explanation:
Explanation:
n=given mass ÷molar mass
make given mass become the subject of the formula by
multiplying the molar mass on both sides of the equation.
n=0.473mol
given mass=??
molar mass=48
therefore,given mass=n×molar mass
=0.473×48
=22.704grams
mass in grams is 22.704grams
acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.
so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base
(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.
Answer:
1.634 molL-1
Explanation:
The mol ration between NH3 and HCl is 1 : 1
Using Ca Va / Cb Vb = Na / Nb where a = acid and b = base
Na = 1
Nb = 1
Ca = 0.208 molL-1
Cb = ?
Va = 19.64 mL
Vb = 25.00mL
Solving for Cb
Cb = Ca Va / Vb
Cb = 0.208 * 19.64 / 25.0
Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)
Using the dilution equation;
C1V1 = C2V2
Initial Concentration, C1 = ?
Initial Volume, V1 = 25.00 mL
Final Volume, V2 = 250 mL
Final Concentration, C2 = 0.1634 molL-1
Solving for C1;
C1 = C2 * V2 / V1
C1 = 0.1634 * 250 / 25.00
C1 = 1.634 molL-1
