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4 years ago

7

Digging downward through a soil profile, how deep would you have to go before you found recognizable fragments of the parent roc

k for the soil?

1 answer:

ohaa [14]4 years ago

3 0

You Willis have to go about 6 -7 ft down

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A ball of silly putty hits andsticks to a bowling ball that was initially at rest. After thecollision, the total kinetic energy

Jobisdone [24]

Answer:

3. less than the kinetic energy of thesilly putty before the collision.

Explanation:

This is because kinetic energy is dependent on the mass and velocity of an object. Mathematically, it is given as:

K. E. = ½*m*v²

Where m = mass

v = velocity

In the case of the silly putty, we know that the masses of the ball of silly putty and the bowling ball are conserved, hence, the kinetic energy depends solely on the velocity at which the object moves.

After the collision with the bowling ball, because of how heavy a bowling ball is, the speed of the silly putty and bowling ball will definitely be less than the speed of the silly putty before collision, i. e. u > v.

Hence, the kinetic energy after collision will be less than the kinetic energy before collision.

7 0

3 years ago

In the previous part, you determined the maximum angle that still allows the crate to remain at rest. If the coefficient of fric

lorasvet [3.4K]

Answer:

B. The maximum angle decreases

Explanation:

If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .

tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .

So the tan of angle of repose θ is proportional to coefficient of static friction.

If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie, it at lower angle of inclination , the object will start slipping .

7 0

3 years ago

a 3 kg piece of putty that is moving with a velocity of 10 m/s collides and sticks to an 8 kg bowling ball that was at rest. wha

defon

The final velocity is 2.7 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the system must be conserved before and after the collision.

Therefore we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 3 kg$ is the mass of the putty

$u_1 = 10 m/s$ is the initial velocity of the putty (we take its direction as positive direction)

$m_2 = 8 kg$ is the mass of the ball

$u_2 = 0 m/s$ is the initial velocity of the ball (at rest)

$v$ is the final combined velocity of the two putty+ball

Re-arranging the equation and substituting the values, we find the final combined velocity:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(3)(10)+0}{3+8}=2.7 m/s$

And the positive sign indicates their final direction is the same as the initial direction of the putty.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

3 0

3 years ago

The core of a star must be at temperature of _____ degrees Celsius for hydrogen fusion to take place. 10,000 100,000 1,000,000 1

disa [49]

The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin.

6 0

3 years ago

If you throw a ball down ward then acceleration immeditely after leaving your hand is

bezimeni [28]

Answer:

9.8m/s²

Explanation:

The acceleration of the ball thrown after leaving my hand is 9.8m/s². This will be the acceleration due to gravity on the body.

Acceleration due to gravity is caused by the pull of the earth on a massive object.
The value of this acceleration is 9.8m/s².
As the ball nears the surface, it comes near zero.

7 0

3 years ago