Answer:
The distribution is as depicted in the attached figure.
Explanation:
From the given data
- The plane wall is initially with constant properties is initially at a uniform temperature, To.
- Suddenly the surface x=L is exposed to convection process such that T∞>To.
- The other surface x=0 is maintained at To
- Uniform volumetric heating q' such that the steady state temperature exceeds T∞.
Assumptions which are valid are
- There is only conduction in 1-D.
- The system bears constant properties.
- The volumetric heat generation is uniform
From the given data, the condition are as follows
<u>Initial Condition</u>
At t≤0

This indicates that initially the temperature distribution was independent of x and is indicated as a straight line.
<u>Boundary Conditions</u>
<u>At x=0</u>
<u />
<u />
This indicates that the temperature on the x=0 plane will be equal to To which will rise further due to the volumetric heat generation.
<u>At x=L</u>
<u />
<u />
This indicates that at the time t, the rate of conduction and the rate of convection will be equal at x=L.
The temperature distribution along with the schematics are given in the attached figure.
Further the heat flux is inferred from the temperature distribution using the Fourier law and is also as in the attached figure.
It is important to note that as T(x,∞)>T∞ and T∞>To thus the heat on both the boundaries will flow away from the wall.
B. Thermal energy is the energy that warms the earths surface.
The answer is "Conduct an experiment" :)
The final velocity is 5.2^2. The initial velocity is 0 . You are using Kinematic equation 3. (V^2=Vo^2+2a(x)) . (5.2^2=2(2.8)x)
27.04=5.6x
27.04/5.6=5.6/5.6x
4.83=x
The answer is 4.83m:)
Missing question: "<span>What is the magnitude of the impulse I imparted to the clay by the floor during the impact?"
Solution:
The impulse is equal to the variation of momentum of the object:
</span>

<span>where m is the mass of the object and </span>

is the variation of velocity of the object during the impact.
By using energy conservation, we can calculate the velocity of the object before the impact. In fact, the initial potential energy of the object is all converted into kinetic energy before the impact:

from which we find v:

This is the velocity of the object just before the impact. After the impact, the object comes to rest: this means that the variation of velocity of the object is equal to 4.75 m/s. Therefore, the impulse is