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Lyrx [107]
2 years ago
8

Star Twinkle but planet do not why​

Physics
1 answer:
V125BC [204]2 years ago
7 0

Answer:The total variation in the amount of light entering our eye is not dectiable therefore planets do not twinkle.

Explanation:Stars twinkle, while planets (usually) shine steadily. Why? Stars twinkle because … they're so far away from Earth that, even through large telescopes, they appear only as pinpoints. ... Planets shine more steadily because … they're closer to Earth and so appear not as pinpoints, but as tiny disks in our sky.As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

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A train crosses a bridge that is 1300 m long in 1 minute and 5 seconds.
Nat2105 [25]

Answer:

I'm pretty sure it's 20m/s because 1300m divided by 65 seconds is 20 so I think it's 20m/s

Explanation:

3 0
2 years ago
How does a large star create the elements? at what element does the star stop making new elements?
Dahasolnce [82]
They are fused in the core of the star due to great pressures and temperatures.  They are made all the way through iron.  At that point the star dies.  If it is a really large star it will become a supernova when it dies, creating all of the elements beyond iron as well, but only in its death.  No star can create anything beyond iron in its life cycle
4 0
3 years ago
two circular loops of wire, each containing a single turn, have the same radius of 4.0 cm and a common center. the planes of the
REY [17]

The magnetic field at center of circular loops of wire is 3.78 x 10¯⁵ T.

We need to know about the magnetic field at the center of circular loops of wire to solve this problem. The magnetic field at the center can be determined as

B = μ₀ . I / 2r

where B is magnetic field, μ₀ is vacuum permeability (4π×10¯⁷ H/m), I is the current and r is radius.

From the question above, we know that:

r = 4 cm = 0.04 m

I = 1.7 A

By substituting the parameter, we get

B = μ₀ . I / 2r

B = 4π×10¯⁷ . 1.7 / (2.0.04)

B = 2.67 x 10¯⁵ T

Due to the perpendicular plane of loops, the total magnetic field at center will be

Btotal = √(2(B²))

Btotal = √(2(2.67 x 10¯⁵²))

Btotal = 3.78 x 10¯⁵ T

Find more on magnetic field at: brainly.com/question/7802337

#SPJ4

3 0
1 year ago
What does the energy hill represent on an energy diagram?
creativ13 [48]

Answer:

In my opinion I think the answer is C you don't have to choose C

8 0
3 years ago
Which particles in an atom are acted upon by the strong force? A. Electrons and neutrons B. Neutrons and protons O C. Protons an
BARSIC [14]

\large \sf \pmb{B) \: Neutrons \:  and  \: Protons}

  • <em>Neutrons And Protons</em> is a particles in an atom and are acted upon by the strong force.
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