Answer:
W = 7.06 J
Explanation:
From the given information the spring constant 'k' can be calculated using the Hooke's Law.

Now, using this spring constant the additional work required by F to stretch the spring can be found.
The work energy theorem tells us that the work done on the spring is equal to the change in the energy. Therefore,
![W = U_2 - U_1\\W = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2 = \frac{1}{2}(275.13)[0.29^2 - 0.18^2] = 7.06~J](https://tex.z-dn.net/?f=W%20%3D%20U_2%20-%20U_1%5C%5CW%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx_2%5E2%20-%20%5Cfrac%7B1%7D%7B2%7Dkx_1%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28275.13%29%5B0.29%5E2%20-%200.18%5E2%5D%20%3D%207.06~J)
Answer:NH3
Explanation: product s are the result of the equation
Answer:
.00135 j
Explanation:
K.E. = 1/2 m v^2
= 1/2 * .03 * .3^2 = .00135 j
The east component of the cars displacement is 17.3 miles.
Trigonometric ratio is used to show the relationship between the sides of a right angled triangle and its angles.
Let x represent the east component of the cars displacement.
Using trigonometric ratio:
cos(30) = x / 20
x = 20 * cos(30)
x = 17.3 miles
The east component of the cars displacement is 17.3 miles.
Find out more on Trigonometric ratio at: brainly.com/question/1201366
Answer:
34.6 m/s
Explanation:
From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg
Final mass will be 31.5+25.9=57.4 kg
From formula of momentum
M1v1=m2v2
Making v2 the subject of the formula then

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then
