All categories

3 years ago

As a chemical reaction occurs, the thermometer in the container records a drop in temperature. What is true of the reaction?

2 answers:

4 0

When a chemical reaction occurs and the thermometer in the container records a drop in temperature the reaction is exothermic because heat was released by the reaction.

B. The reaction is exothermic because heat was released by the reaction. is your answer.

Hoped I helped!

tester [92]3 years ago

3 0

Answer:

The reaction is exothermic because heat was released by the reaction.

Explanation:

'exothermic' means a reaction released heat over the time of the experiment.

'endothermic' means that the reaction released cold over the experiment.

You might be interested in

What is the reduction potential of a hydrogen electrode that is still at standard pressure, but has ph = 5.65 , relative to the

Zigmanuir [339]

Answer:

$\boxed{\text{-0.275 V}}$

Explanation:

We must use the Nernst equation

$E = E^{\circ} - \dfrac{RT}{zF} \ln Q$

1. Write the equation for the cell reaction

If you want the reduction potential, the pH 5.65 solution is the cathode, and the cell reaction is

E°/V

Anode: H₂(1 bar) ⇌ 2H⁺(1 mol·L⁻¹) + 2e⁻; 0

Cathode: 2H⁺(pH 5.65) + 2e⁻ ⇌ H₂(1 bar); 0

Overall: 2H⁺ (pH 5.65) ⇌ 2H⁺(1 mol·L⁻¹); 0

Step 2. Calculate E°

(a) Data

E° = 0

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C

n = 2

F = 96 485 C/mol

pH = 5.65

Calculations:

T = 25 + 273.15 = 298.15 K

$\text{H}^{+} = 10^{\text{-pH}} = 2.24 \times 10^{-5}\text{ mol/\L}\\\\Q = \dfrac{\text{[H}^{+}]_{\text{prod}}^{2}}{\text{[H}^{+}]_{\text{react}}^{2}} = \dfrac{(1.00)^{2}}{(2.24 \times 10^{-5})^{2}} =2.00 \times 10^{9}\\\\\\E = 0 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln{2.00 \times 10^{9}}\\\\= -0.01285 \times 21.41 = \textbf{-0.275 V}\\\text{The cell potential for the cell as written is }\boxed{\textbf{-0.275 V}}$

6 0

3 years ago

This begins as a nebula

PSYCHO15rus [73]

The answer is star...

5 0

3 years ago

Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):

Tom [10]

NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest

4 0

3 years ago

PLEASE PLEASE HELP Calculate the mass of 3.4 moles of nitric acid (HNO3)

Elza [17]

Molar mass of nitric acid (HNO3) =atomic mass of hydrogen + atomic mass of nitrogen +3x atomic mass of oxygen . The molar mass of nitric acid (HNO3) is 63.0144 gram per mole, but you have 3.4 moles. Therefore; the answer is 63.0144 g/mole x 3.4 moles = 214.24896 grams.

6 0

3 years ago

The diagrams are showing a cell undergoing a mitotic division at different points of Anaphase. Use the ABC labels on the drawing

Advocard [28]

Answer:

where is the drawing? I can't help if I can't see it sorry

7 0

3 years ago

Read 2 more answers