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garik1379 [7]
3 years ago
9

A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow

er and good tires on good pavement, the maximum forward force on the truck is 18,000 N.
Part A

What is the maximum possible acceleration the truck can give the SUV?

Express your answer to two significant figures and include the appropriate units.

a =

Part B

At this acceleration, what is the force of the SUV's bumper on the truck's bumper?

Express your answer to two significant figures and include the appropriate units.

Fsuv on truck =
Physics
2 answers:
Setler [38]3 years ago
7 0

Answer:

A) the maximum possible acceleration = 3.83 m/s²

B) F(SUV bumper) = 2400  kg *3.83 m/s² = 9192 N = 92 * 10² N

Explanation:

Step 1: Data given

Mass of the truck = 2300 kg

Mass of the SUV = 2400 kg

The maximum forward force on the truck is 18000 N

Step 2: What is the maximum possible acceleration the truck can give the SUV?

Total mass = MAss truck + mass SUV

Total mass = 2300 kg + 2400 kg

Total mass = 4700 kg

Acceleration = Force / mass

The maximum possible acceleration = 18000 N / 4700 kg

the maximum possible acceleration = 3.83 m/s²

Step 3: At this acceleration, what is the force of the SUV's bumper on the truck's bumper?

F = m * a

F(trucks bumper) = 2300 kg *3.83 m/s² = 8809 N

F(SUV bumper) = 2400  kg *3.83 m/s² = 9192 N = 92 * 10² N

IrinaK [193]3 years ago
3 0

Answer:

a) a_{max} = 3.8\,\frac{m}{s^{2}}, b) F = 9260\,N

Explanation:

a) The maximum possible acceleration that the truck can give to the SUV is:

a_{max} = \frac{18,000\,N}{2,400\,kg+2300\,kg}

a_{max} = 3.8\,\frac{m}{s^{2}}

b) The equation of equilibrium for the truck is:

18,000\,N - F = (2,300\,kg)\cdot (3.8\,\frac{m}{s^{2}})

The force of the SUV's bumper on the truck's bumper is:

F = 9260\,N

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b)When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.

c)The velocity of the bolt just before it reaches the ground is -43.6 m/s

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Hi there!

a) Let´s calculate how much distance it is the last 11% of the fall:

96 m · 0.11 = 10.56 m

So, we have to find how much time it takes the bolt to pass from a height of 10.56 m to the ground.

First, let´s calculate how much time it takes the bolt to reach a height of 10.56 m. For that we can use this equation:

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v0 = initial velocity.

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g = acceleration due to gravity.

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h = h0 + 1/2 · g · t²

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<u>When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.</u>

Now, we can calculate how much time it takes to fall the last 10.56 m.

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h = h0 + v0 · t + 1/2 · g · t²

We have to find the time at which h = 0 (the bolt hits the ground)

0 = 10.56 m - 41.2 m/s · t - 1/2 · 9.8 m/s² · t²

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v = v0 + g · t

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v = -43.6 m/s

<u>The velocity of the bolt just before it reaches the bolt is -43.6 m/s</u>

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