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Stolb23 [73]
3 years ago
11

Solve by graphing. x2 2x - 8 = 0 a. –2, 4 b. 2, –4 c. 2, –4 d. –2, 4

Mathematics
2 answers:
Luba_88 [7]3 years ago
4 0
Well, to solve, garph the equation y=x^2+2x-8 and y=0
see where they intersect

anyway the easier way is to factor but anyway
0=(x-4)(x+2)


anyway

solution is x=4 and -2

A and D are answers (they are same)
Hatshy [7]3 years ago
4 0

Answer:

Option B and C are same, which are the correct answers.

Step-by-step explanation:

The given graph shows the plot for x²+2x-8=0

Here the graph crosses the x axis at points -4 and 2.

So the roots of the equations are -4 and 2

Option B and C are same, which are the correct answers.

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Can someone help plz
KIM [24]
I think the answer is B.
8 0
3 years ago
Please help!!!!!I’ll mark you as brainliest!!!!!!
statuscvo [17]

Answer: B $50,700

Step-by-step explanation:  Subtract expenses from earnings...

65,000-4,900-7,400-2,000=50,700

8 0
3 years ago
Read 2 more answers
The ratio of boys to girls in a school is 5:4. if there are 500 girls , how many boys are there in the school?
lana [24]

Answer:

The number of boys in the school is;

625

Explanation:

Given that the ratio of boys to girls in a school is 5:4;

5\colon4

And there are 500 girls in the school.

The number of boys in the school will be;

\begin{gathered} \frac{B}{G}=\frac{5}{4} \\ G=500 \\ B=\frac{5\times G}{4}=\frac{5\times500}{4} \\ B=625 \end{gathered}

Therefore, the number of boys in the school is;

625

3 0
1 year ago
How would you prove these two triangles conrguent?
Crank

Answer:

SSS

Step-by-step explanation:

4 0
3 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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