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GrogVix [38]
3 years ago
11

Dalton's Atomic Theory states A) that an atom is predominantly empty space. B) that matter is composed of small indestructible p

articles. C) that the properties of matter are determined by the properties of atoms. D) that energy is neither created nor destroyed during a chemical reaction. E) that all elements have several isotopes. 2) Identify a solid. A) definite volume and definite shape B) definite volume and no definite shape C) definite shape and no definite volume D) no definite shape and no definite volume 3) A substance that can't be chemically broken down into simpler substances is A) a homogeneous mixture. B) an element. C) an electron. D) a heterogeneous mixture. E) a compound. 4) Two or more substances in variable proportions, where the composi
Chemistry
1 answer:
MrMuchimi3 years ago
5 0

Answer:

1.B. That matter is composed of small indestructible particles.  

2.A. Definite volume and definite shape.

3.B. An element

Explanation:

1.Dalton's atomic theory postulates:

1.It states that matter is composed of atoms that are  indivisible and indestructible.

2.Atoms of an elements are identical .They have same size ,chemical properties and mass.

3.Atoms of one element are different from atoms of another elements.

4.Compounds are composed of atoms of more than one elements.The relative number of atoms of each element in a given compound is always same.

5.Atoms are not created or destroyed during chemical reaction.

Answer: B.That matter is composed of small indestructible particles.  

2.Solid:It is that form of substance which have definite shape and definite volume.

Therefore, option A is true.

Answer:A. Definite volume and definite shape.

3.An element: it is a simpler substance .It cannot be broken into smaller substance by chemical reactions.

Therefore, option B is true.

Answer:B. An element

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Boyle law is a gas law stating the pressure and the volume of a gas have an inverse relationship when held at constant temperature.

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3 years ago
Suppose you want to do an experiment to hear how three different objects with sound when dropped from the same distance. You dro
Alexus [3.1K]
They will fall at different rates because of air resistance
6 0
3 years ago
2NH.
liq [111]

Answer:

N=2

H=6

Explanation:

1.Balance a chemical equation in terms of moles.

2.Use the balanced equation to construct conversion factors in terms of moles.

3.Calculate moles of one substance from moles of another substance using a balanced chemical equation.

The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.

(P.s it could also be where you have to solve it in which you have to simplify it first then solve it.) like adding them all up.

Hope this is the answer. :)

6 0
3 years ago
Acetaldehyde (CH3CHO) undergoes a Wolf-Kishner reaction, which is the addition of hydrazine (H2NNH2) with subsequent addition of
Anarel [89]

Answer:

Reduced, alkane

Explanation:

Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.

This reaction occurs at high temperature.

Alkane formed has a same number of carbon as aldehyde and ketone.

If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.

Here, acetaldehyde is reduced to form ethane.

So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine  with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.

6 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
2 years ago
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