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GrogVix [38]
3 years ago
11

Dalton's Atomic Theory states A) that an atom is predominantly empty space. B) that matter is composed of small indestructible p

articles. C) that the properties of matter are determined by the properties of atoms. D) that energy is neither created nor destroyed during a chemical reaction. E) that all elements have several isotopes. 2) Identify a solid. A) definite volume and definite shape B) definite volume and no definite shape C) definite shape and no definite volume D) no definite shape and no definite volume 3) A substance that can't be chemically broken down into simpler substances is A) a homogeneous mixture. B) an element. C) an electron. D) a heterogeneous mixture. E) a compound. 4) Two or more substances in variable proportions, where the composi
Chemistry
1 answer:
MrMuchimi3 years ago
5 0

Answer:

1.B. That matter is composed of small indestructible particles.  

2.A. Definite volume and definite shape.

3.B. An element

Explanation:

1.Dalton's atomic theory postulates:

1.It states that matter is composed of atoms that are  indivisible and indestructible.

2.Atoms of an elements are identical .They have same size ,chemical properties and mass.

3.Atoms of one element are different from atoms of another elements.

4.Compounds are composed of atoms of more than one elements.The relative number of atoms of each element in a given compound is always same.

5.Atoms are not created or destroyed during chemical reaction.

Answer: B.That matter is composed of small indestructible particles.  

2.Solid:It is that form of substance which have definite shape and definite volume.

Therefore, option A is true.

Answer:A. Definite volume and definite shape.

3.An element: it is a simpler substance .It cannot be broken into smaller substance by chemical reactions.

Therefore, option B is true.

Answer:B. An element

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Explanation:

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UkoKoshka [18]

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3 years ago
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Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)
nikklg [1K]

The elements are samarium (Sm) and silver (Ag).  

<em>Quantum numbers (4,3,-2,+½)  </em>

<em>n</em> = 4: Principal quantum number = 4.  

<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

<em>n</em> = 5: Principal quantum number = 5.  

<em>l</em> = 2: Element has <em>5d</em> electrons  

We get the following table:  

<u>Element </u><em><u>n</u></em><u>  </u><em><u>l m</u></em><u>ₗ mₛ</u><em><u>  </u></em>

<em>  </em>   Y       5<em> </em>2  2 +½  

    Zr      5 2  1 +½  

    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

7 0
3 years ago
A student is trying to identify a clear liquid that he finds in a beaker in the classroom. He thinks the liquid might be either
kumpel [21]

Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.

Explanation:

density

ρ

=

Mass

Volume

, and thus units of

g

⋅

m

L

−

1

are reasonable.

For this problem:

17.4

⋅

m

L

×

0.798

⋅

g

⋅

m

L

−

1

≅

14

⋅

g

but A i supposed?

3 0
3 years ago
Element Y has two natural isotopes Y-63 (62.940 amu) and Y-65 (64.928 amu). Calculate the atomic mass of element Y, given the ab
djverab [1.8K]

Answer:

Average atomic mass = 63.553 amu.

Explanation:

Given data:

Abundance of Y-63 = 69.17%

Abundance of Y-65 = 100 - 69.17 = 30.83%

Atomic mass of Y-63 = 62.940 amu

Atomic mass of Y-65 = 64.928 amu

Atomic mass of Y = ?

Solution:

Average atomic mass= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass= (62.940×69.17)+(64.928×30.83) /100

Average atomic mass =  4353.560 + 2001.730 / 100

Average atomic mass = 6355.29 / 100

Average atomic mass = 63.553 amu.

5 0
3 years ago
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