2 Na + Cl₂ → 2 NaCl
Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag
CH₄ + 2 O₂ → CO₂ + 2 H₂O
are oxidation-reduction reactions
Explanation:
In the oxidation-reduction reaction there is a component which accept electrons and it is reduced and another component which donates electrons and it is oxidized.
Now in the case of the reaction of copper (Cu) with silver nitrate (AgNO₃):
Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag
Cu⁰ with a oxidation number 0 donates 2 electrons⁻ and is transformed in Cu⁺² with the oxidation number 2+.
Ag⁺ with a oxidation number 1+ accepts 1 electron⁻ and is transformed in Ag with the oxidation number 0.
In the case of CH₄ + 2 O₂ → CO₂ + 2 H₂O reaction we have:
C⁴⁻ with a oxidation number +4 donates 8 electrons⁻ and is transformed in C⁴⁺ with the oxidation number 4+.
O⁰ with a oxidation number 0 accepts 2 electrons⁻ and is transformed in O²⁻ with the oxidation number 2-.
And in the case of 2 Na + Cl₂ → 2 NaCl reaction we have:
Na⁰ with a oxidation number 0 donates 1 electron⁻ and is transformed in Na⁺ with the oxidation number 1+.
Cl⁰ with a oxidation number 0 accepts 1 electron⁻ and is transformed in Clwith the oxidation number 1-.
Learn more about:
oxidation-reduction reactions
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