<span>Answer
is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643
1/s.
k</span>₂ = 0,00828
1/s.
T₁ = 622 K.
T₂ = 666 K.
R = 8,3145 J/Kmol.
1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K =
0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>
6.16 I did the math so I know it is correct
Computer models are generally used to predict long term events
Letter A is balanced correctly
Pressure of the gas P1 = 30.7 kpa
When it doubled P2 = 61.4 kpa
Temperature T1 = 0 => T1 =. 0 + 273 =273
Temperature T2 =?
We have pressure temperature equation P1T1 = P2T2
=> T2 = P1T1 / P2 = (30.7 x 273) / 61.4 = 136.5
So the temperature for doubling the pressure is 136.5.