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Leya [2.2K]
3 years ago
9

What is the universal solvent? A:oil B:acid C:water D:hydrogen

Chemistry
2 answers:
Delvig [45]3 years ago
6 0
C: WATER Yw mf , you better pass your test too
Mademuasel [1]3 years ago
3 0

Answer:

C: water

Explanation:

Water dissolves more substances than other liquids. That is why it is called a universal solvent.

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6 0
3 years ago
What masses of monobasic and dibasic sodium phosphate will you use to make 250 mL of 0.1 M sodium phosphate buffer, pH = 7?
Oduvanchick [21]

Answer:

  • Mass of monobasic sodium phosphate = 1.857 g
  • Mass of dibasic sodium phosphate = 1.352 g

Explanation:

<u>The equilibrium that takes place is:</u>

H₂PO₄⁻ ↔ HPO₄⁻² + H⁺    pka= 7.21 (we know this from literature)

To solve this problem we use the Henderson–Hasselbalch (<em>H-H</em>) equation:

pH = pka + log\frac{[A^{-} ]}{[HA]}

In this case [A⁻] is [HPO₄⁻²], [HA] is [H₂PO₄⁻], pH=7.0, and pka = 7.21

If we use put data in the <em>H-H </em>equation, and solve for [HPO₄⁻²], we're left with:

7.0=7.21+log\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\ -0.21=log\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\\\10^{-0.21} =\frac{[HPO4^{-2} ]}{[H2PO4^{-} ]}\\0.616 * [H2PO4^{-}] = [HPO4^{-2}]

From the problem, we know that [HPO₄⁻²] + [H₂PO₄⁻] = 0.1 M

We replace the value of [HPO₄⁻²] in this equation:

0.616 * [H₂PO₄⁻] + [H₂PO₄⁻] = 0.1 M

1.616 * [H₂PO₄⁻] = 0.1 M

[H₂PO₄⁻] = 0.0619 M

With the value of [H₂PO₄⁻]  we can calculate [HPO₄⁻²]:

[HPO₄⁻²] + 0.0619 M = 0.1 M

[HPO₄⁻²] = 0.0381 M

With the concentrations, the volume and the molecular weights, we can calculate the masses:

  • Molecular weight of monobasic sodium phosphate (NaH₂PO₄)= 120 g/mol.
  • Molecular weight of dibasic sodium phosphate (Na₂HPO₄)= 142 g/mol.

  • mass of NaH₂PO₄ = 0.0619 M * 0.250 L * 120 g/mol = 1.857 g
  • mass of Na₂HPO₄ = 0.0381 M * 0.250 L * 142 g/mol = 1.352 g
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arsen [322]
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Miranda gets a small cut on her thumb after she breaks a beaker, and she begins to look around for the lab first aid kit.
sleet_krkn [62]

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