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RideAnS [48]
3 years ago
5

What is the difference in electronegativity of each bond for both formaldehyde and ammonia?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

                     The chemical formula of Formaldehyde is H₂CO and the structural formula is attached below,

                     The chemical formula of Ammonia is NH₃ and the structural formula is attached below,

FORMALDEHYDE:

                              As shown in structure, there are two different types of bonds in formaldehyde,

        (i) C-H Bond

        (ii) C-O Bond

So the electronegativity difference of these bonds are,

(i) C-H Bond

           Electronegativity of Carbon      =  2.5

           Electronegativity of Hydrogen  =  2.1

                                                               _______

           Electronegativity Difference  =       0.4 (non-polar bond)

(ii) C-O Bond

           Electronegativity of Oxygen      =  3.5

           Electronegativity of Carbon       =  2.5

                                                               _______

           Electronegativity Difference  =       1.0   (polar bond)

AMMONIA:

                              As shown in structure, there is one type of bond in ammonia, and that is N-H bond

So the electronegativity difference in this bond is,

N-H Bond

           Electronegativity of Nitrogen      =  3.0

           Electronegativity of Hydrogen    =  2.1

                                                               _______

           Electronegativity Difference  =        0.9   (polar bond)

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Answer:

2Al2O3 (l) ---> 4Al (l) + 3O2 (g)

Explanation:

The reaction is the electrolysis of aluminium oxide. It decomposes aluminium oxide (Al2O3) into aluminium metal (Al) and Oxygen (O2). In this process, aluminium oxide is molten (liquid state) so that ions can move to complete the electricity circuit.

Al2O3 (l) ---> Al (l) + O2 (g)

Balance the equation:

2Al2O3 (l) ---> 4Al (l) + 3O2 (g)

4 0
3 years ago
n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?
victus00 [196]

Answer:

The coefficient that should be inserted in front of chlorine is 2

Explanation:

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As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.

Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.

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Helium

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Convert 123 in scientific notation
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✡ Answer: 1.23*10^2 ✡


- - Add a decimal at the end (to the right) and count till you get to the first number.
So now you have 1.23

- - Now you always want to times it by 10 to the power of how many times you moved it over, in this case, 2

Final answer: 1.23*10^2

✡Hope this helps✡


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