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Nonamiya [84]
3 years ago
7

Calculate the grams of so2 gas present at stp in a 5.9 l container.

Chemistry
1 answer:
nata0808 [166]3 years ago
7 0

<u>Answer:</u> The mass of sulfur dioxide gas at STP for given amount is 16.8 g

<u>Explanation:</u>

At STP conditions:

22.4 L of volume is occupied by 1 mole of a gas.

So, 5.9 L of volume will be occupied by = \frac{1mol}{22.4L}\times 5.9L=0.263mol

Now, to calculate the mass of a substance, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sulfur dioxide gas = 0.263 mol

Molar mass of sulfur dioxide gas = 64 g/mol

Putting values in above equation, we get:

0.263mol=\frac{\text{Mass of sulfur dioxide gas}}{64g/mol}\\\\\text{Mass of sulfur dioxide gas}=(0.263mol\times 64g/mol)=16.8g

Hence, the mass of sulfur dioxide gas at STP for given amount is 16.8 g

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The scientific models are used because they allow scientists to make predictions and make it easier for scientists to avoid using data. option A and C is correct.

<h3>What are scientific models?</h3>

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The biggest advantage is that scientists do not have to check the given data which are written into books they can perform their experiment and can conclude the data by performing experiment.

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