Charles's Law.
<u>V1</u><u> </u> = <u>V2</u>
T1 T2
V1 = 720 mL
T1 = 22°C
T2 = 106°C
V2 = ?
then,
<u>7</u><u>2</u><u>0</u><u> </u> = <u>V2</u><u> </u>
22 106
V2 = 3469 mL
All you can conclude is that something must be burning with an orange flame.
Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:
2Na + 2H₂O → 2NaOH + H₂ + heat
So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.
The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
Answer:
9842kJ of energy are released
Explanation:
Based on the reaction:
2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂(g) + 10 H₂O (g) + 5720 kJ
<em>When 2 moles of C₄H₁₀ react with 13 moles of O₂ there are released 5720 kJ of energy</em>
As molar mass of C₄H₁₀ is 58.12g/mol, moles in 200.0g of the hydrocarbon are:
200.0g C₄H₁₀ ₓ (1mol / 58.12g) =<em> 3.441 moles of C₄H₁₀</em>
<em> </em>
As 2 moles of C₄H₁₀ release 5720kJ of energy, 3.441 moles of C₄H₁₀ release:
3.441 moles C₄H₁₀ ₓ (5720kJ / 2 moles C₄H₁₀) = <em>9842kJ of energy are released</em>
