Answer:17
Explanation:NH3 = 14 + 3 = 17 g/mole.
<h3>
Answer:</h3>
3.11 moles
<h3>
Explanation:</h3>
We are given 56 g of water (H₂O)
Required to calculate the number of moles of water.
- The relationship between moles, mass and molar mass is given by;
- Moles = Mass ÷ molar mass
in this case;
- Mass of water = 56 g
- Molar mass of water = 18.02 g/mol
Therefore;
Moles of water = 56 g ÷ 18.02 g/mol
= 3.11 moles
Therefore, moles of water in 56 g will be 3.11 moles
Answer:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12
Explanation:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12 sike firgue it out on your own
The limiting reagent : NH₃
<h3>Further explanation</h3>
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant
Reaction
4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)
mol NH₃ :
mol O₂ :
mol ratio
NH₃ :
O₂ :
Limiting reactants : NH₃ (smaller ratio)
Answer : The measurement units were biased.
Explanation : While the wildlife researcher weighed all the raccoons that were trapped only in the suburban neighborhood neglected the count of the raccoons in whole state. As per the statement stated in the problem "weighed all the raccoons that were trapped in suburban neighborhoods" clearly shows the confirmation of the same.