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mars1129 [50]
4 years ago
11

With the help of word equations identify the products of heating candle wax?​

Chemistry
2 answers:
DochEvi [55]4 years ago
7 0

Answer:

carbon dixiode and water

Explanation:

Y_Kistochka [10]4 years ago
3 0

Explanation:

The word equation for the burning of a candle is wax plus oxygen yields carbon dioxide and water. This is an exothermic reaction that produces both light and heat.

The fuel for a burning candle is the wax. There are many different types of wax with a corresponding number of chemical formulas, but they are all hydrocarbons. Hydrocarbons are molecules made from hydrogen and carbon.

Burning the wax pulls the hydrogen and carbon in the wax apart and recombines them with oxygen from the atmosphere. This is an oxidation reaction. The resulting carbon dioxide and water are gases that disperse in the air.

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­­2K + 2HBr → 2 KBr + H2
Inessa [10]

Answer:

\large \boxed{\text{0.0503 g}}

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:   39.10    80.41                2.016  

            2K  +  2HBr ⟶ 2KBr + H₂

m/g:     5.5      4.04

a) Limiting reactant

(i) Calculate the moles of each reactant  

\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:  

The molar ratio of H₂:K is 1:2.

\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}

From HBr:  

The molar ratio of H₂:HBr is 3:2.  

\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }

3 0
3 years ago
How do you determine which tool to use for lab activities?
Gnesinka [82]

Answer:

It all depends what your working with and what experiment your planning on doing .

Explanation:

Say if you were working with chemicals you would the tools that would help you protect your body like gloves,googles, apron , etc

So in conclusion it depends what your doing to know what tools you are going to need

4 0
4 years ago
I break and shatter easily and I am not shiny. What am I?
Troyanec [42]

Answer:

Uhh a heart? i.dk

7 0
2 years ago
Which is true of the enthalpy of a reaction?
salantis [7]

Answer: I think it's B

6 0
3 years ago
Rank the following hydroxides in order of increasing aqueous basicity: Al(OH)₃, (OH)₃, In(OH)₃
vovangra [49]

The correct answer is B(OH)3 <AI(OH)3 < In(OH)3.

The metallic character of the group 1 elements first increases from Boron to Aluminium, then decreases from Aluminium to Thallium because of high ionization Enthalpy. Also, the larger size of the ion, the lesser is the ionization of Enthalpy.

Basic nature of the hydroxides of group 13 increases on moving down the group as the electro-positive character of elements increases.

Therefore, the correct order of increasing aqueous basicity is as follows:

B(OH)3 <AI(OH)3 < In(OH)3

What is the basic nature of group 13?

The metallic charecter of the elements affects their fundamental characteristics. The basicity rises as the metallic character does, and vice versa. Therefore, as we move lower in any given group, the atomic radius of the elements increases. Higher radii indicate that it would become increasingly challenging for the nucleus to rule over the electrons in the valency shell. Consequently, there will be a greater inclination for electron release. As a result, the metallic properties will improve, increasing the basicity of the oxides. Therefore, it follows that the basicity of the oxides would rise as we go down in a group.

To learn more about hydroxides refer the link:

brainly.com/question/10134219

#SPJ4

7 0
2 years ago
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