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A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the

IgorC [24]

Answer: The empirical formula for the given compound is $Cr_2S_3$

Explanation : Given,

Mass of product = 0.963 g

Mass of Cr = 0.500 g

Mass of S = 0.963 g - 0.500 g = 0.463 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Cr = $\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles$

Moles of S = $\frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.

For Cr = $\frac{0.00962}{0.00962}=1$

For S = $\frac{0.0145}{0.00962}=1.5$

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of Cr : S = 1 : 1.5

The ratio of Cr : S = 2 : 3

Step 3: Taking the mole ratio as their subscripts.

The ratio of Cr : S = 2 : 3

Hence, the empirical formula for the given compound is $Cr_2S_3$

8 0

4 years ago

I’m so confused please help on how to balance all these equations!

Arisa [49]

Answer:

Explanation:

Synthesis Reaction:

The reaction in which two or more molecules or compound combine together to form a new compound.

1. K + Cl₂ --------> KCl

Balanced equation

2 K + Cl₂ -------->2 KCl

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2. Ca + F₂ --------> CaF₂

Balanced equation

Ca + F₂ --------> CaF₂

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3. Ag + S --------> AgS

Balanced equation

2Ag + S --------> Ag₂S

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4. Na + I₂ --------> NaI

Balanced equation

2 Na + I₂ --------> 2 NaI

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5. Mg + O₂ --------> MgO

Balanced equation

2 Mg + O₂ --------> 2 MgO

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6. H₂ + Cl₂ --------> HCl

Balanced equation

H₂ + Cl₂ --------> 2 HCl

____________________________

Decomposition reaction:

when one compound breaks down into 2 or more molecule or components.

7. Cs₂O --------> Cs + O₂

Balanced equation

2 Cs₂O --------> 4 Cs + O₂

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8. H₂O --------> H₂ + O₂

Balanced equation

2 H₂O --------> 2 H₂ + O₂

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9. MgBr₂ --------> Mg + Br₂

Balanced equation

MgBr₂ --------> Mg + Br₂

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10. AlCl₃ --------> Al + Cl₂

Balanced equation

2 AlCl₃ --------> 2 Al + 3 Cl₂

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11. KI --------> K + I₂

Balanced equation

2 KI --------> 2K + I₂

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12. NaCl --------> Na + Cl₂

Balanced equation

2 NaCl --------> 2 Na + Cl₂

_______________________________

Combustion:

when a fuel burn in the presence of oxygen and produces carbon dioxide and water.

13. C₃H₈ + O₂ --------> CO₂ + H₂O

Balanced equation

C₃H₈ + 5 O₂ --------> 3 CO₂ + 4 H₂O

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14. C₂H₄ + O₂ --------> CO₂ + H₂O

Balanced equation

C₂H₄ + 3 O₂ --------> 2 CO₂ + 2 H₂O

7 0

4 years ago

4 pts

Digiron [165]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

$\frac{1mole}{69.723g} *\frac{43.9g}{1} =0.63MOLga$

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

$\frac{4molesGa}{3moles02} =\frac{0.63molesga}{xmoleso2}$

Cross multiply and solve for x:

4x=1.89

x=47 molesO₂

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

7 0

3 years ago

If you dilute 125 mL of a 2.5 M solution of Lici to 1.0 L, determine the new

Rama09 [41]

Answer:

0.31M is the new concentration of the solution

Explanation:

The solution is diluted from 125mL to 1.0L = 1000mL. The dilution is of:

1000mL / 125mL = 8 times.

That means the concentration of the diluted solution is 8 times lower than the original solution. That is:

2.5M / 8 times =

<h3>0.31M is the new concentration of the solution</h3>

7 0

3 years ago

Substance in which all atoms are alike

Troyanec [42]

Answer:

That substance is an element.

Explanation:

Atoms in a substance have the same identity, that substance is an element. in other words if all atoms are alike then it is an element.

Ive gotten this question asked to me before.

8 0

3 years ago