When the antimatter is atomic antihydrogen, a small amount of it is mixed with excess atomic hydrogen (gathered from interstellar space during flight).
<h3>What is antimatter ?</h3>
According to contemporary physics, antimatter is described as being made up of the opposite particles from "ordinary" matter, or their "partners." Only a few nanograms of antiparticles have been created artificially, but tiny quantities of antiparticles are produced every day at particle accelerators and in natural processes like cosmic ray collisions and some types of radioactive decay. However, only a small portion of these antiparticles have been successfully bound together in experiments to form antiatoms. Antimatter has never been built in a macroscopic amount due to its extremely high cost, complexity in synthesis, and handling.
A particle and its antiparticle, such as a proton and an antiproton, theoretically have the same mass but the opposite electric charge and other variations in quantum numbers.
To learn more about antimatter from the given link:
brainly.com/question/518346
#SPJ4
Answer:
Mechanical advantage = load/<u>effort</u>
Explanation:
Mechanical advantage is like a ratio of load to effort and many machines like pulleys depend on this relationship between load and effort for it to work.
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
To know more about mole ratio, visit the below link:
brainly.com/question/504601
A pure substance and a element
Answer:
158 mL
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 99.0 KPa
Initial volume (V₁) = 300 mL
Final pressure (P₂) = 188 KPa
Final volume (V₂) =?
The final volume of the gas can be obtained by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
99 × 300 = 188 × V₂
29700 = 188 × V₂
Divide both side by 188
V₂ = 29700 / 188
V₂ = 158 mL
Therefore, the final volume of the gas is 158 mL.
