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miss Akunina [59]
3 years ago
6

The pictures are the answers

Chemistry
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

C.

Explanation:

If the students want to know at what percent of CO2 in the air the plant will grow at the fastest, then the percent of CO2 should be a different value for each plant in the table.

There are 2 tables that have different values for the CO2 - the tables in answer choices C and D.

Since the students only want to know how the amount of CO2 affects the plant, every other variable should remain constant.

The only answer choice that has a changing value for the percent of CO2 and a constant value for every other variable is C.

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What is the specific heat of a 123 g substance that requires 4.56 J of heat in
vladimir1956 [14]

Answer:  A. 0.00301J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,\Delta T=T_f-T_i=12.32^0C

Putting in the values, we get:

4.56J=123g\times c\times 12.32^0C

c=0.00301J/g^0C

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is 0.00301J/g^0C

8 0
3 years ago
I need help with this question
malfutka [58]
What question do you need help with
5 0
3 years ago
Read 2 more answers
If a gas occupies 4600 mL at 0.9 atm and 195°C, what is the new volume in ml
Bumek [7]

Answer:

The new volume is 2415 mL

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.

Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:

P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} =k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:

\frac{P}{T} =k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T} =k

Having two different states, an initial state and an final state, it is true:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

In this case:

  • P1= 0.9 atm
  • V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
  • T1= 195 °C= 468 °K (being 0°C=273°K)

The final state 2 is in STP conditions:

  • P2= 1 atm
  • V2= ?
  • T2= 0°C= 273 °K

Replacing:

\frac{0.9 atm*4.6L}{468K} =\frac{1 atm*V2}{273K}

Solving:

V2=\frac{0.9 atm*4.6L}{468K}*\frac{273K}{1 atm}

V2= 2.415 L =2,415 mL

<u><em>The new volume is 2415 mL</em></u>

6 0
3 years ago
Calculate the pressure kPa of 0.421 mole of helium gas at 254 degree celsius when it occupies a volume of 3.32 L.
Ronch [10]
I didn’t understand the question ♥️
3 0
3 years ago
Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
maw [93]

Answer:  d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g) \Delta H=+1411.1kJ

Reversing the reaction, changes the sign of \Delta H

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)

\Delta H=-1411.1kJ

On multiplying the reaction by \frac{1}{2} , enthalpy gets half:

0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol

Thus the enthalpy change for the given reaction is -705.55kJ

7 0
3 years ago
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