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sleet_krkn [62]
3 years ago
10

Liquids and solids are left out of the equilibrium constant expression because their concentrations remain constant during react

ions. What is the molarity concentration of liquid water at 25.0 LaTeX: ^\circ ∘C given that its density is 0.997 g/mL at that temperature?
a.23.5 M
b.0.997 M
c.0.180 M
d.0.156 M
e.55.3 M
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

55.3 M

Explanation:

Given temperature = 25°C

Density = 0.997 g/mL

Based on density the mass of water per L = 997 grams

The molar mass of water = 18

The moles of water = \frac{mass}{molarmass}=\frac{997}{18}=55.3

The molarity is defined as the moles of water per litre.

The moles = 55.3

Volume = 1 L

So molarity = 55.3 /1 = 55.3 M

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M_{A}V_{A}=M_{B}V_{B}\\(80.0)(4.00)=V_{B}(12.4)\\V_{B}=\frac{(80.0)(4.00)}{12.4} \approx \boxed{25.8 \text{ mL}}

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Which of the following elements is least likely to form a cation that will then form an ionic bond with an ion of a Group 7A ele
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F because it NEVER forms any cations in chemical reactions
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4+4=?
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A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0
OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL

Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

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3 years ago
If distance, d, is proportional to time, t, and at time t =2.00 seconds, the distance is 6.20 m, find the distance when t = 3.50
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At 3.5s the distance would be 10.85

Find 1/4th of 2.00 and add that to 6.2
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