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rewona [7]
3 years ago
5

What is the active component of dynamite

Chemistry
1 answer:
yawa3891 [41]3 years ago
4 0
The active component in dynamite is Nitroglycerin, and it is in most of the other explosive material.
Hoped I helped:D
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Which statement explains why carbon-14 dating cannot be used to date ancient rocks?
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Answer:b

Explanation:

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4 years ago
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What volume (in L) of carbon dioxide will be produced from the reaction of 37.4 L of oxygen?
Anna [14]

Answer:

21.4 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Volume of oxygen  = 37.4 L

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L

Now we will compare:

                              O₂             :              CO₂    

                              156.9         :              89.66

                                37.4         :             89.66/156.9×37.4 = 21.4 L

So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.

3 0
3 years ago
What solutions would you propose to a car manufacturer if its car rated poorly in a crash test? Please explain your answer.
scoundrel [369]

Answer:

fix the car better

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Calculate the speed of a wave that has a wavelength of 8 meters and a frequency of 16 meters per second (m/s).
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Answer:

Assume that you move one end of a rope up and down just once to generate a wave in the rope. How long will take the wave to travel down the rope to the other end? It depends on the speed of the wave.

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Calculate the molality of a 20.0 percent by weight aqueous solution of nh4cl. (molecular weight: nh4cl = 53.5)
cestrela7 [59]
Unfortunately the data provided doesn't include the DENSITY of the ammonium chloride solution and molarity is defined as moles per volume. So without the density, the calculation of the molarity is impossible. But fortunately, there are tables available that do provide the required density and for a 20% solution by weight, the density of the solution is 1.057 g/ml.  
So 1 liter of solution will mass 1057 grams and the mass of ammonium chloride will be 0.2 * 1057 g = 211.4 g. The number of moles will then be 211.4 g / 53.5 g/mol = 3.951401869 mol. Rounding to 3 significant digits gives a molarity of 3.95.  
Now assuming that your teacher wants you to assume that the solution masses 1.00 g/ml, then the mass of ammonium chloride will only be 200g, and that is only (200/53.5) = 3.74 moles.   
So in conclusion, the expected answer is 3.74 M, although the correct answer using missing information is 3.95 M.
8 0
4 years ago
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