Answer:
Three half lives corresponds to (12)3 . So a 18 quantity of the original isotope is retained. And the percentage of quantity of a radioactive material that remains after 5 half-lives will be . ∴NN0×100=10032=3.125.
Answer:

Explanation:
1. Calculate the moles of HCl

2. Calculate the volume of dilute HCl

Answer:
b) Both p orbitals are perpendicular to the F−Be−F bond axes.
Explanation:
Be has 2 electrons in its valence shell, subshell s is fulfilled, so it has no unpaired electrons in its ground state to make bonds with F. So, it can promote the electrons to the 2p orbital and will having sp hybridization.
The bond between the orbitals sp and the p orbital of F are in opposite directions but the same ax. The two bonds are equivalent, and the molecule had a linear geometry. The two unhybridized p orbitals on Be are vacant, and so they are perpendicular to the F-Be-F bond axes.
Iron is matter; since the smallest unit of matter is atoms, iron could be brokolen down into atoms. unlike iron, water is a molecule made from atoms that were chemically combined, so water could be broken down into molecules.
<h3>Answer : 2C + 3H2 -> C2H6</h3>
<h3>Step and explanation</h3>
Condition : graphite + hydrogen gas
Chemical formula : C + H2
Reaction formula :
C + H2 -> C2H6
#First, you see the number of atom
•Product
C = 1
H = 2
•Reactant
C = 2
H = 6
<em>#</em><em>N</em><em>o</em><em>t</em><em>e</em><em> </em><em>that</em><em>,</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>chemical</em><em> </em><em>reaction</em><em> </em><em>both</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>atom</em><em> </em><em>in</em><em> </em><em>product</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>equal</em><em> </em><em>in</em><em> </em><em>reactant</em><em> </em><em>so</em><em>,</em><em> </em><em>you</em><em> </em><em>think</em><em> </em><em>what</em><em> </em><em>number</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>put</em><em> </em><em>Infront</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>chemical</em><em> </em><em>formula</em><em> </em><em>so</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>atom</em><em> </em><em>equal</em>
2C + 3H2 -> C2H6
#Now check again
•Product
C = 2
H = 6
•Reactant
C = 2
H6
#Now, its equal. The bold one is the balance chemical reaction
<h3>Note (just incase u dont know)</h3>
Reactant -> product (the thing you get after reaction)