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3 years ago

Which of these prevents conduction from occuring?

Chemistry

2 answers:

valentinak56 [21]3 years ago

7 0

C. Equal temperatures

BigorU [14]3 years ago

3 0

C is the correct answer

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Which of the following is part of photosynthesis, but not part of cellular respiration?

Licemer1 [7]

Answer:

Explanation:

plants need sunlight to eat. so that's why

8 0

3 years ago

Type the correct answer in the box. Express your answer to three significant figures.

VladimirAG [237]

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 = 96.1 g

Molar mass of Ca(NO3)2 = 164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

Therefore, # moles of Ca3(PO4)2 produced = 0.0589 * 1/3 = 0.0196 moles

Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g

7 0

3 years ago

Read 2 more answers

What can be absorbed or produced as the result of a chemical reaction???

tia_tia [17]

Heat can be absorbed or produced

6 0

3 years ago

Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour

Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>

Energy (cal) = 6.85×10⁵ cal
Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0

2 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago