Tar pits.
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Answer: Substances on Earth can exist in one of four phases, but mostly, they exist in one of three: solid, liquid or gas. Learn the six changes of phase: freezing, melting, condensation, vaporization, sublimation and deposition. Intermolecular forces are forces between molecules that determine the physical properties of liquids and solids. 11.2 Vaporization and Vapor Pressure— vaporization is the conversion of a liquid to a gas (vapor), and the quantity of heat associated with this phase change is known as the enthalpy (heat) of vaporization. When kinetic energy is increasing molecules are simply moving faster. However, when the potential energy is increasing molecules are changing phases. Therefore, when the potential energy is increasing is when the molecule is changing phases. Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing). ... Changing the amount of heat energy usually causes a temperature change.
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The heat lost is ![-7.32*10^-^5J](https://tex.z-dn.net/?f=-7.32%2A10%5E-%5E5J)
The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.
<h3>Heat Transfer</h3>
This is the heat transferred from a body of higher temperature to a body of lower temperature.
![Q = mc(\delta)T](https://tex.z-dn.net/?f=Q%20%3D%20mc%28%5Cdelta%29T)
- Q = Heat Transfer
- m = mass = 1277g
- ΔT = change in temperature
![\delta T = (400 - 273) - (263 - 273) = \\ \delta T = T_2 - T_1\\ \delta T = -10 - 127\\ \delta T = -137^0C](https://tex.z-dn.net/?f=%5Cdelta%20T%20%3D%20%28400%20-%20273%29%20-%20%28263%20-%20273%29%20%3D%20%5C%5C%0A%5Cdelta%20T%20%3D%20T_2%20-%20T_1%5C%5C%0A%5Cdelta%20T%20%3D%20-10%20-%20127%5C%5C%0A%5Cdelta%20T%20%3D%20-137%5E0C)
We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.
Solving for heat transfer
![Q = mc\delta T\\ Q = 1277 * 4.186 * -137\\ Q = -732336.514J](https://tex.z-dn.net/?f=Q%20%3D%20mc%5Cdelta%20T%5C%5C%0AQ%20%3D%201277%20%2A%204.186%20%2A%20-137%5C%5C%0AQ%20%3D%20-732336.514J)
The heat loss is approximately ![-7.32*10^-^5J](https://tex.z-dn.net/?f=-7.32%2A10%5E-%5E5J)
Learn more on heat transfer here;
brainly.com/question/16055406